Chapter 19, Problem 75A

Interpretation Introduction

Interpretation:

Using the rules of oxidation number, the given table is to be completed.

Concept introduction:

To find oxidation number of an element, there are rules assigned.

Applying these rules, one can calculate oxidation number of every element present in the compound.

Answer to Problem 75A

Element	Oxidation number	Rule
$KinKBr$	+1	2
$BrinKBr$	-1	8
$ClinC{l}_2$	0	1
$KinKCl$	+1	7
$ClinKCl$	-1	2 and 8
$BrinB{r}_2$	0	1

Explanation of Solution

Table of determining rules is used to write the rule number given in table and oxidation number of elements to be find out.

Oxidation number of $BrinKBr$ =

$\begin{array}{l}1+x=0\\ x=-1\end{array}$(By rule 2 and 8) Oxidation number of $ClinC{l}_2$ = 0 (By rule 1)

Oxidation number of $KinKCl$ = +1 (By rule2)

Conclusion

Thus,

Element	Oxidation number	Rule
$KinKBr$	+1	2
$BrinKBr$	-1	8
$ClinC{l}_2$	0	1
$KinKCl$	+1	7
$ClinKCl$	-1	2 and 8
$BrinB{r}_2$	0	1