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(a)
Interpretation:
The two half
Concept introduction:
Redox reaction is the combination of oxidation and reduction.
(a)
Answer to Problem 71A
Oxidation half reaction:
2NH3→N2+6e−+6H+
Reduction half reaction:
Pb2++2e−→Pb
Explanation of Solution
The given reaction is:
PbO+NH3→N2+Pb+H2O
Equation in ionic form is:
Pb2++NH3→N2+Pb
Thus half reactions are:
Oxidation half reaction:
2NH3→N2+6e−+6H+
Reduction half reaction:
Pb2++2e−→Pb
(b)
Interpretation:
The two half reactions of given balanced redox reaction is to be written.
Concept introduction:
Redox reaction is the combination of oxidation and reduction.
Oxidation half reaction represents oxidation and reduction half reaction represents reduction.
(b)
Answer to Problem 71A
Oxidation half reaction:
S2O32−→S2O42−+2e−
Reduction half reaction:
I2+2e−→2I−
Explanation of Solution
The given reaction in ionic form is:
I2+S2O32−→S2O42−+I−
Thus half reactions are:
Oxidation half reaction:
S2O32−→S2O42−+2e−
Reduction half reaction:
I2+2e−→2I−
(c)
Interpretation:
The two half reactions of given balanced redox reaction is to be written.
Concept introduction:
Redox reaction is the combination of oxidation and reduction.
Oxidation half reaction represents oxidation and reduction half reaction represents reduction.
(c)
Answer to Problem 71A
Thus half reactions are:
Oxidation half reaction:
Sn→Sn+2+2e−
Reduction half reaction:
2H++2e−→H2
Explanation of Solution
The given reaction is:
Sn+2HCl→SnCl2+H2
Equation in ionic form is:
Sn+2H+→Sn+2+H2
Thus half reactions are:
Oxidation half reaction:
Sn→Sn+2+2e−
Reduction half reaction:
2H++2e−→H2
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