Chapter 19.2, Problem 30SSC

Interpretation Introduction

Interpretation:

Oxidation and reduction half reactions are to be written for given redox reaction.

Concept introduction:

Oxidation half-reaction: The half part of redox reaction which represent oxidation.

Reduction half-reaction: The half part of redox reaction which represent reduction.

Answer to Problem 30SSC

Oxidation half reaction is:

$Pb\to P{b}^{+2}+2e^{-}$

Reduction half reaction is:

$P{d}^{+2}+2e^{-}\to Pd$

Explanation of Solution

Oxidation half-reaction shows process of oxidation and the number of electrons involved in the process.

Reduction half-reaction shows process of reduction and the number of electrons involved in the process.

The given reaction in ionic form is:

$Pb+P{d}^{+2}\to P{b}^{+2}+Pd$

Thus,

Oxidation half reaction is:

$Pb\to P{b}^{+2}+2e^{-}$

Reduction half reaction is:

$P{d}^{+2}+2e^{-}\to Pd$

Conclusion

Oxidation half-reaction: The half part of ionic redox reaction which represent oxidation.

Reduction half-reaction: The half part of ionic redox reaction which represent reduction.