Chapter 19.1, Problem 13SSC

Interpretation Introduction

(a)

Interpretation:

The oxidation number of $I$ needs to be determined in $I{O}_4{}^{-}$

Concept introduction:

Oxidation number: It is defined as charge the atom would have if electrons are not shared but transfer completely.

Answer to Problem 13SSC

+7

Explanation of Solution

The oxidation number of $I$ is calculated as:

$\begin{array}{c}x+\left(-2\times 4\right)=-1\\ x-8=-1\\ x=+7\end{array}$

Interpretation Introduction

(b)

Interpretation:

The oxidation number of $B$ needs to be determined in $B_4{O}_7{}^{2-}$

Concept introduction:

Oxidation number: It is defined as charge the atom would have if electrons are not shared but transfer completely.

Answer to Problem 13SSC

+3

Explanation of Solution

The oxidation number of $B$ is calculated as:

$\begin{array}{c}4\times x+\left(-2\times 7\right)=-2\\ 4x-14=-2\\ 4x=12\\ x=3\end{array}$

Interpretation Introduction

(c)

Interpretation:

The oxidation number of $Mn$ needs to be determined in $Mn{O}_4{}^{-}$

Concept introduction:

Oxidation number: It is defined as charge the atom would have if electrons are not shared but transfer completely.

Answer to Problem 13SSC

+7

Explanation of Solution

The oxidation number of $Mn$ is calculated as:

$\begin{array}{c}x+\left(-2\times 4\right)=-1\\ x-8=-1\\ x-7=0\\ x=7\end{array}$

Interpretation Introduction

(d)

Interpretation:

The oxidation number of $N$ needs to be determined in $N{H}_2{}^{-}$

Concept introduction:

Oxidation number: It is defined as charge the atom would have if electrons are not shared but transfer completely.

Answer to Problem 13SSC

-3

Explanation of Solution

The oxidation number of $N$ is calculated as:

$\begin{array}{c}x+\left(1\times 2\right)=-1\\ x+2=-1\\ x=-3\end{array}$