Interpretation: The given redox reaction is to be balanced using a half-reaction method.
Concept Introduction :
A half-reaction method to balance the ionic equation in acidic solution involves:-
- Assign the oxidation number to each element.
- Check which element is oxidized and which element is reduced. Write
oxidation and reduction half-reactions. - Check the change in oxidation number for the elements which are oxidized and reduced.
- Then add enough hydrogen ions and water molecules to the equation to balance hydrogen atoms on both sides.
- Adjust the coefficients so that number of electrons lost in oxidation is equal to electrons gained in reduction.
- Add the balanced half-reactions.

Answer to Problem 70A
A balanced equation in ionic form
MnO4−+5Fe2++8H+→5Fe+3+Mn+2+4H2O
A balanced equation in given form
2KMnO4+10FeSO4+8H2SO4→5Fe2(SO4)3+2MnSO4+K2SO4+8H2O
Explanation of Solution
The given redox reaction is:
KMnO4+FeSO4+H2SO4→Fe2(SO4)3+MnSO4+K2SO4+H2O
A reaction in the ionic form:
MnO4−+Fe2+→Fe+3+Mn+2
Assigning the oxidation number-
+7MnO4−++2Fe2+→+3Fe+3++2Mn+2
The oxidation numbers of atoms show that
Fe is oxidized and Mn is reduced.
Change in oxidation number of Fe=+1
Change in oxidation number of Mn=−5
Fe2+→Fe+3+e−
MnO4−+5e−→Mn+2
Balancing the atoms and charges:
Fe2+→Fe+3+e−
MnO4−+5e−+8H+→Mn+2+4H2O
Now, adding both reactions after multiplying reduction half cell reaction with 2
MnO4−+5Fe2++8H+→5Fe+3+Mn+2+4H2O
A balanced equation in ionic form
MnO4−+5Fe2++8H+→5Fe+3+Mn+2+4H2O
A balanced equation in given form
2KMnO4+10FeSO4+8H2SO4→5Fe2(SO4)3+2MnSO4+K2SO4+8H2O
Chapter 19 Solutions
Chemistry: Matter and Change
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