Chapter 19, Problem 10STP

Interpretation Introduction

Interpretation:

The species oxidized and reduced are to be identified in a given redox reaction.

Concept introduction:

The species whose oxidation takes place is said to be oxidized. On oxidation, oxidation number of the species is increased.

The species whose reduction takes place is said to be reduced. On reduction, oxidation number of the species is decreased.

Answer to Problem 10STP

$I_2$is oxidized and $Pb{O}_2$is reduced.

Explanation of Solution

Oxidation state of each participant is mentioned:

${\stackrel{0}{I}}_2+\stackrel{+4}{Pb}{\stackrel{-2}{O}}_2\to \stackrel{+5}{I}{\stackrel{-2}{O}}_3{}^{-}+\stackrel{+2}{P{b}^{+2}}$

Oxidation number of I is increasing so it gets oxidized and Oxidation number of Pb is decreasing so it gets reduced.

Conclusion

$I_2$is oxidized to $I{O}_3{}^{-}$ and $Pb{O}_2$is reduced to

$P{b}^{2+}$