Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Question
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Chapter 1.8, Problem 5PSA

a.

To determine

The conclusion for the following statements.

a.

Expert Solution
Check Mark

Answer to Problem 5PSA

“If d, then f”

Explanation of Solution

Given information: The statements are as follows:

   a b   ---- Equation 1 d~c  ---- Equation 2 ~ca  ---- Equation 3            bf     ---- Equation 4

Concept Used:

Every conditional statement “If p, then q” has three other statements associated with it.

A converse (If q, then p)

An inverse (If~p,then~q.)

A contrapositive (If~q,then~p.)

Calculation:

  From Equation 1 and Equation 4,we get a f   ---- Equation 5From Equation 2 and Equation 3,we get da   ---- Equation 6From Equation 5 and Equation 6,we get df  

Conclusion:

  "If d,then f ",i.e. d f.

b.

To determine

The conclusion for the given statements.

b.

Expert Solution
Check Mark

Answer to Problem 5PSA

“If s, then (p”

Explanation of Solution

Given information: The statements are as follows:

   p ~q  ---- Equation 1            rq     ---- Equation 2            sr     ---- Equation 3

Concept Used:

Every conditional statement “If p, then q” has three other statements associated with it.

A converse (If q, then p)

An inverse (If~p,then~q.)

A contrapositive (If~q,then~p.)

Calculation:

  I we take converse of Equation 1,we get           q ~p  ---- Equation 4From Equation 3 and Equation 2,we get           sq      ---- Equation 5From Equation 4 and Equation 5,we get           s ~p

Conclusion:

  "If s,then ~ p ",i.e. s ~ p.

c.

To determine

To conclude a result from the statements.

c.

Expert Solution
Check Mark

Answer to Problem 5PSA

If bobcats begin to browse, then horses head for home.

Explanation of Solution

Given information: We rewrite the statements in symbolic form. wc   ---- Equation 1            gh    ---- Equation 2            cg    ---- Equation 3            bw   ---- Equation 4

Concept Used:

Every conditional statement “If p, then q” has three other statements associated with it.

A converse (If q, then p)

An inverse (If~p,then~q.)

A contrapositive (If~q,then~p.)

Calculation:

From Equation 4 and Equation 1, we get

             bc   ---- Equation 5

From Equation 3 and Equation 2, we get

             ch   ---- Equation 6

From Equation 5 and Equation 6, we get

  bh  Conclusion:

  "If b,then h",i.e. b h.

Chapter 1 Solutions

Geometry For Enjoyment And Challenge

Ch. 1.1 - Prob. 11PSBCh. 1.1 - Prob. 12PSBCh. 1.1 - Prob. 13PSCCh. 1.1 - Prob. 14PSCCh. 1.2 - Prob. 1PSACh. 1.2 - Prob. 2PSACh. 1.2 - Prob. 3PSACh. 1.2 - Prob. 4PSACh. 1.2 - Prob. 5PSACh. 1.2 - Prob. 6PSACh. 1.2 - Prob. 7PSACh. 1.2 - Prob. 8PSACh. 1.2 - Prob. 9PSACh. 1.2 - Prob. 10PSACh. 1.2 - Prob. 11PSACh. 1.2 - Prob. 12PSBCh. 1.2 - Prob. 13PSBCh. 1.2 - Prob. 14PSBCh. 1.2 - Prob. 15PSBCh. 1.2 - Prob. 16PSBCh. 1.2 - Prob. 17PSBCh. 1.2 - Prob. 18PSBCh. 1.2 - Prob. 19PSCCh. 1.2 - Prob. 20PSCCh. 1.2 - Prob. 21PSCCh. 1.2 - Prob. 22PSCCh. 1.2 - Prob. 23PSCCh. 1.3 - Prob. 1PSACh. 1.3 - Prob. 2PSACh. 1.3 - Prob. 3PSACh. 1.3 - Prob. 4PSACh. 1.3 - Prob. 5PSACh. 1.3 - Prob. 6PSACh. 1.3 - Prob. 7PSACh. 1.3 - Prob. 8PSACh. 1.3 - Prob. 9PSACh. 1.3 - Prob. 10PSBCh. 1.3 - Prob. 11PSBCh. 1.3 - Prob. 12PSBCh. 1.3 - Prob. 13PSBCh. 1.3 - Prob. 14PSBCh. 1.3 - Prob. 15PSCCh. 1.3 - Prob. 16PSCCh. 1.3 - Prob. 17PSCCh. 1.4 - Prob. 1PSACh. 1.4 - Prob. 2PSACh. 1.4 - Prob. 3PSACh. 1.4 - Prob. 4PSACh. 1.4 - Prob. 5PSACh. 1.4 - Prob. 6PSACh. 1.4 - Prob. 7PSACh. 1.4 - Prob. 8PSACh. 1.4 - Prob. 9PSACh. 1.4 - Prob. 10PSACh. 1.4 - Prob. 11PSBCh. 1.4 - Prob. 12PSBCh. 1.4 - Prob. 13PSBCh. 1.4 - Prob. 14PSCCh. 1.4 - Prob. 15PSCCh. 1.5 - Prob. 1PSACh. 1.5 - Prob. 2PSACh. 1.5 - Prob. 3PSACh. 1.5 - Prob. 4PSACh. 1.5 - Prob. 5PSACh. 1.5 - Prob. 6PSACh. 1.5 - Prob. 7PSACh. 1.5 - Prob. 8PSACh. 1.5 - Prob. 9PSACh. 1.5 - Prob. 10PSACh. 1.5 - Prob. 11PSACh. 1.5 - Prob. 12PSACh. 1.5 - Prob. 13PSACh. 1.5 - Prob. 14PSACh. 1.5 - Prob. 15PSACh. 1.5 - Prob. 16PSACh. 1.5 - Prob. 17PSACh. 1.5 - Prob. 18PSBCh. 1.5 - Prob. 19PSBCh. 1.5 - Prob. 20PSBCh. 1.5 - Prob. 21PSBCh. 1.5 - Prob. 22PSCCh. 1.5 - Prob. 23PSCCh. 1.5 - Prob. 24PSCCh. 1.6 - Prob. 1PSACh. 1.6 - Prob. 2PSACh. 1.6 - Prob. 3PSACh. 1.6 - Prob. 4PSACh. 1.6 - Prob. 5PSACh. 1.6 - Prob. 6PSACh. 1.6 - Prob. 7PSBCh. 1.6 - Prob. 8PSBCh. 1.6 - Prob. 9PSBCh. 1.6 - Prob. 10PSCCh. 1.6 - Prob. 11PSCCh. 1.6 - Prob. 12PSDCh. 1.7 - Prob. 1PSACh. 1.7 - Prob. 2PSACh. 1.7 - Prob. 3PSACh. 1.7 - Prob. 4PSACh. 1.7 - Prob. 5PSACh. 1.7 - Prob. 6PSACh. 1.7 - Prob. 7PSACh. 1.7 - Prob. 8PSBCh. 1.7 - Prob. 9PSBCh. 1.7 - Prob. 10PSBCh. 1.7 - Prob. 11PSBCh. 1.7 - Prob. 12PSBCh. 1.7 - Prob. 13PSCCh. 1.7 - Prob. 14PSCCh. 1.8 - Prob. 1PSACh. 1.8 - Prob. 2PSACh. 1.8 - Prob. 3PSACh. 1.8 - Prob. 4PSACh. 1.8 - Prob. 5PSACh. 1.8 - Prob. 6PSBCh. 1.8 - Prob. 7PSBCh. 1.8 - Prob. 8PSBCh. 1.8 - Prob. 9PSBCh. 1.8 - Prob. 10PSCCh. 1.9 - Prob. 1PSACh. 1.9 - Prob. 2PSACh. 1.9 - Prob. 3PSACh. 1.9 - Prob. 4PSACh. 1.9 - Prob. 5PSACh. 1.9 - Prob. 6PSBCh. 1.9 - Prob. 7PSBCh. 1.9 - Prob. 8PSBCh. 1.9 - Prob. 9PSBCh. 1.9 - Prob. 10PSBCh. 1.9 - Prob. 11PSBCh. 1.9 - Prob. 12PSCCh. 1.9 - Prob. 13PSCCh. 1.9 - Prob. 14PSCCh. 1.9 - Prob. 15PSCCh. 1 - Prob. 1RPCh. 1 - Prob. 2RPCh. 1 - Prob. 3RPCh. 1 - Prob. 4RPCh. 1 - Prob. 5RPCh. 1 - Prob. 6RPCh. 1 - Prob. 7RPCh. 1 - Prob. 8RPCh. 1 - Prob. 9RPCh. 1 - Prob. 10RPCh. 1 - Prob. 11RPCh. 1 - Prob. 12RPCh. 1 - Prob. 13RPCh. 1 - Prob. 14RPCh. 1 - Prob. 15RPCh. 1 - Prob. 16RPCh. 1 - Prob. 17RPCh. 1 - Prob. 18RPCh. 1 - Prob. 19RPCh. 1 - Prob. 20RPCh. 1 - Prob. 21RPCh. 1 - Prob. 22RPCh. 1 - Prob. 23RPCh. 1 - Prob. 24RPCh. 1 - Prob. 25RPCh. 1 - Prob. 26RPCh. 1 - Prob. 27RPCh. 1 - Prob. 28RPCh. 1 - Prob. 29RPCh. 1 - Prob. 30RPCh. 1 - Prob. 31RPCh. 1 - Prob. 32RPCh. 1 - Prob. 33RPCh. 1 - Prob. 34RPCh. 1 - Prob. 35RPCh. 1 - Prob. 36RPCh. 1 - Prob. 37RPCh. 1 - Prob. 38RPCh. 1 - Prob. 39RPCh. 1 - Prob. 40RPCh. 1 - Prob. 41RPCh. 1 - Prob. 42RPCh. 1 - Prob. 43RP
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