Concept explainers
a
The possible names of the line containing the points.
a
Answer to Problem 1RP
Possible names are
Explanation of Solution
Given information:
A quadrilateral ABCD
So, the possible name of line segment can be
b.
b.
Answer to Problem 1RP
The side containing the angle ∠ABC is AB and BC.
Explanation of Solution
Given information:
A quadrilateral ABCD
The side containing the angle ∠ABC is AB and BC.
c.
c.
Answer to Problem 1RP
The common side of ∠2 and ∠4 is DF
Explanation of Solution
Given information:
A quadrilateral ABCD
The common side of ∠2 and ∠4 is DF
d.
d.
Answer to Problem 1RP
The horizontal ray containing the end point C is BC.
Explanation of Solution
Given information:
A quadrilateral ABCD
A ray is defined as a part of a line with a start point but no end point.
The horizontal ray containing the end point C is BC.
e.
e.
Answer to Problem 1RP
∠BAD
∠2
∠ABC
Explanation of Solution
Given information:
A quadrilateral ABCD
f.
To find whether the two angle are same.
f.
Answer to Problem 1RP
Both the angles are same.
Explanation of Solution
Given information:
A quadrilateral ABCD
The angle FCD and angle DCE represent the same angle as point E and F are on the same line segment.
g.
g.
Answer to Problem 1RP
The angle B is the angle containing the side AB and BC.
Explanation of Solution
Given information:
A quadrilateral ABCD
The side containing the angle ∠ABC is AB and BC.
h.
h.
Answer to Problem 1RP
Explanation of Solution
Given information:
A quadrilateral ABCD
Ray FC is on ray EC so their union is EC.
i.
i.
Answer to Problem 1RP
Explanation of Solution
Given information:
A quadrilateral ABCD
Common part in ray EC and FA is segment EF
j.
j.
Answer to Problem 1RP
Explanation of Solution
Given information:
A quadrilateral ABCD
Ray BA and ray BE together forms ∠ABE
k.
k.
Answer to Problem 1RP
Explanation of Solution
Given information:
A quadrilateral ABCD
Line AC and DR intersect at point A.
l.
l.
Answer to Problem 1RP
Explanation of Solution
Given information:
A quadrilateral ABCD
Angle AFD and line segment CE both intersect to give line segment EF.
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