Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Question
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Chapter 1.1, Problem 6PSA

a.

To determine

To Find: The all possible name of given angle.

a.

Expert Solution
Check Mark

Answer to Problem 6PSA

  RPO,P

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.1, Problem 6PSA , additional homework tip  1

Concept Used:

Angle is the intersection of two common rays.

Calculation:

The given angle OPR can be named as

  RPO,P

Conclusion:

  RPO,P

b.

To determine

To Find: The vertex of the angle TOS .

b.

Expert Solution
Check Mark

Answer to Problem 6PSA

  S

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.1, Problem 6PSA , additional homework tip  2

Concept Used:

Angle is the intersection of two common rays having one common vertex.

Calculation:

The vertex of the given angle TOS is S .

Conclusion:

The vertex of the given angle TOS is S .

c.

To determine

To Find: The number of angles formed using the vertex R.

c.

Expert Solution
Check Mark

Answer to Problem 6PSA

Three angles formed using the vertex R.

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.1, Problem 6PSA , additional homework tip  3

Concept Used:

Angle is the intersection of two common rays having one common vertex.

Calculation:

The angles formed using the vertex R are SRO,ORPand SRP

Thus, three angles formed using the vertex R.

Conclusion:

Three angles formed using the vertex R.

d.

To determine

To Find: The all possible name of given angle.

d.

Expert Solution
Check Mark

Answer to Problem 6PSA

  PST,OST,TSO,O

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.1, Problem 6PSA , additional homework tip  4

Concept Used:

Angle is the intersection of two common rays.

Calculation:

The given angle TSP can be named as

  PST,OST,TSO,O

Conclusion:

  PST,OST,TSO,O

e.

To determine

To Find: The number of triangles formed in the given figure.

e.

Expert Solution
Check Mark

Answer to Problem 6PSA

Eight triangles are in the given figure.

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.1, Problem 6PSA , additional homework tip  5

Concept Used:

Triangle is a three sided closed polygon.

Calculation:

The triangles in the given figures are

  ΔOPR,ΔORS,ΔOST,ΔOTP,ΔPRS,ΔRST,ΔSTPand ΔTPR

Thus there are eight triangles in the given figure.

Conclusion:

Eight triangles in the given figure.

Chapter 1 Solutions

Geometry For Enjoyment And Challenge

Ch. 1.1 - Prob. 11PSBCh. 1.1 - Prob. 12PSBCh. 1.1 - Prob. 13PSCCh. 1.1 - Prob. 14PSCCh. 1.2 - Prob. 1PSACh. 1.2 - Prob. 2PSACh. 1.2 - Prob. 3PSACh. 1.2 - Prob. 4PSACh. 1.2 - Prob. 5PSACh. 1.2 - Prob. 6PSACh. 1.2 - Prob. 7PSACh. 1.2 - Prob. 8PSACh. 1.2 - Prob. 9PSACh. 1.2 - Prob. 10PSACh. 1.2 - Prob. 11PSACh. 1.2 - Prob. 12PSBCh. 1.2 - Prob. 13PSBCh. 1.2 - Prob. 14PSBCh. 1.2 - Prob. 15PSBCh. 1.2 - Prob. 16PSBCh. 1.2 - Prob. 17PSBCh. 1.2 - Prob. 18PSBCh. 1.2 - Prob. 19PSCCh. 1.2 - Prob. 20PSCCh. 1.2 - Prob. 21PSCCh. 1.2 - Prob. 22PSCCh. 1.2 - Prob. 23PSCCh. 1.3 - Prob. 1PSACh. 1.3 - Prob. 2PSACh. 1.3 - Prob. 3PSACh. 1.3 - Prob. 4PSACh. 1.3 - Prob. 5PSACh. 1.3 - Prob. 6PSACh. 1.3 - Prob. 7PSACh. 1.3 - Prob. 8PSACh. 1.3 - Prob. 9PSACh. 1.3 - Prob. 10PSBCh. 1.3 - Prob. 11PSBCh. 1.3 - Prob. 12PSBCh. 1.3 - Prob. 13PSBCh. 1.3 - Prob. 14PSBCh. 1.3 - Prob. 15PSCCh. 1.3 - Prob. 16PSCCh. 1.3 - Prob. 17PSCCh. 1.4 - Prob. 1PSACh. 1.4 - Prob. 2PSACh. 1.4 - Prob. 3PSACh. 1.4 - Prob. 4PSACh. 1.4 - Prob. 5PSACh. 1.4 - Prob. 6PSACh. 1.4 - Prob. 7PSACh. 1.4 - Prob. 8PSACh. 1.4 - Prob. 9PSACh. 1.4 - Prob. 10PSACh. 1.4 - Prob. 11PSBCh. 1.4 - Prob. 12PSBCh. 1.4 - Prob. 13PSBCh. 1.4 - Prob. 14PSCCh. 1.4 - Prob. 15PSCCh. 1.5 - Prob. 1PSACh. 1.5 - Prob. 2PSACh. 1.5 - Prob. 3PSACh. 1.5 - Prob. 4PSACh. 1.5 - Prob. 5PSACh. 1.5 - Prob. 6PSACh. 1.5 - Prob. 7PSACh. 1.5 - Prob. 8PSACh. 1.5 - Prob. 9PSACh. 1.5 - Prob. 10PSACh. 1.5 - Prob. 11PSACh. 1.5 - Prob. 12PSACh. 1.5 - Prob. 13PSACh. 1.5 - Prob. 14PSACh. 1.5 - Prob. 15PSACh. 1.5 - Prob. 16PSACh. 1.5 - Prob. 17PSACh. 1.5 - Prob. 18PSBCh. 1.5 - Prob. 19PSBCh. 1.5 - Prob. 20PSBCh. 1.5 - Prob. 21PSBCh. 1.5 - Prob. 22PSCCh. 1.5 - Prob. 23PSCCh. 1.5 - Prob. 24PSCCh. 1.6 - Prob. 1PSACh. 1.6 - Prob. 2PSACh. 1.6 - Prob. 3PSACh. 1.6 - Prob. 4PSACh. 1.6 - Prob. 5PSACh. 1.6 - Prob. 6PSACh. 1.6 - Prob. 7PSBCh. 1.6 - Prob. 8PSBCh. 1.6 - Prob. 9PSBCh. 1.6 - Prob. 10PSCCh. 1.6 - Prob. 11PSCCh. 1.6 - Prob. 12PSDCh. 1.7 - Prob. 1PSACh. 1.7 - Prob. 2PSACh. 1.7 - Prob. 3PSACh. 1.7 - Prob. 4PSACh. 1.7 - Prob. 5PSACh. 1.7 - Prob. 6PSACh. 1.7 - Prob. 7PSACh. 1.7 - Prob. 8PSBCh. 1.7 - Prob. 9PSBCh. 1.7 - Prob. 10PSBCh. 1.7 - Prob. 11PSBCh. 1.7 - Prob. 12PSBCh. 1.7 - Prob. 13PSCCh. 1.7 - Prob. 14PSCCh. 1.8 - Prob. 1PSACh. 1.8 - Prob. 2PSACh. 1.8 - Prob. 3PSACh. 1.8 - Prob. 4PSACh. 1.8 - Prob. 5PSACh. 1.8 - Prob. 6PSBCh. 1.8 - Prob. 7PSBCh. 1.8 - Prob. 8PSBCh. 1.8 - Prob. 9PSBCh. 1.8 - Prob. 10PSCCh. 1.9 - Prob. 1PSACh. 1.9 - Prob. 2PSACh. 1.9 - Prob. 3PSACh. 1.9 - Prob. 4PSACh. 1.9 - Prob. 5PSACh. 1.9 - Prob. 6PSBCh. 1.9 - Prob. 7PSBCh. 1.9 - Prob. 8PSBCh. 1.9 - Prob. 9PSBCh. 1.9 - Prob. 10PSBCh. 1.9 - Prob. 11PSBCh. 1.9 - Prob. 12PSCCh. 1.9 - Prob. 13PSCCh. 1.9 - Prob. 14PSCCh. 1.9 - Prob. 15PSCCh. 1 - Prob. 1RPCh. 1 - Prob. 2RPCh. 1 - Prob. 3RPCh. 1 - Prob. 4RPCh. 1 - Prob. 5RPCh. 1 - Prob. 6RPCh. 1 - Prob. 7RPCh. 1 - Prob. 8RPCh. 1 - Prob. 9RPCh. 1 - Prob. 10RPCh. 1 - Prob. 11RPCh. 1 - Prob. 12RPCh. 1 - Prob. 13RPCh. 1 - Prob. 14RPCh. 1 - Prob. 15RPCh. 1 - Prob. 16RPCh. 1 - Prob. 17RPCh. 1 - Prob. 18RPCh. 1 - Prob. 19RPCh. 1 - Prob. 20RPCh. 1 - Prob. 21RPCh. 1 - Prob. 22RPCh. 1 - Prob. 23RPCh. 1 - Prob. 24RPCh. 1 - Prob. 25RPCh. 1 - Prob. 26RPCh. 1 - Prob. 27RPCh. 1 - Prob. 28RPCh. 1 - Prob. 29RPCh. 1 - Prob. 30RPCh. 1 - Prob. 31RPCh. 1 - Prob. 32RPCh. 1 - Prob. 33RPCh. 1 - Prob. 34RPCh. 1 - Prob. 35RPCh. 1 - Prob. 36RPCh. 1 - Prob. 37RPCh. 1 - Prob. 38RPCh. 1 - Prob. 39RPCh. 1 - Prob. 40RPCh. 1 - Prob. 41RPCh. 1 - Prob. 42RPCh. 1 - Prob. 43RP

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