Chapter 1.1, Problem 10PSA

a.

To determine

To Calculate: The area of rectangle.

Answer to Problem 10PSA

  $\text{Area of rectangle =}21.5c{m}^2$

Explanation of Solution

Given:

A rectangle with sides 2.5 cm and 8.6 cm long

  

Concept Used:

  $\text{Area of rectangle = }Length\times Breadth$

Calculation:

Here, length of rectangle = 8.6 cm

And breadth of rectangle = 2.5 cm

  $\therefore \text{Area of rectangle = }8.6cm\times 2.5cm=21.5c{m}^2$

Conclusion:

  $\text{Area of rectangle =}21.5c{m}^2$

b.

To determine

To Calculate: The perimeter of rectangle.

Answer to Problem 10PSA

  $\text{Perimeter of rectangle =}22.2cm$

Explanation of Solution

Given:

A rectangle with sides 2.5 cm and 8.6 cm long

  

Concept Used:

  $\text{Perimeter of rectangle = 2}\left(Length+Breadth\right)$

Calculation:

Here, length of rectangle = 8.6 cm

And breadth of rectangle = 2.5 cm

  $\begin{array}{l}\therefore \text{Perimeter of rectangle = 2}\left(Length+Breadth\right)\\ =\text{2}\left(8.6cm+2.5cm\right)\\ =\text{2}\times 11.1cm\\ =22.2cm\end{array}$

Conclusion:

  $\text{Perimeter of rectangle =}22.2cm$