Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Chapter 1.5, Problem 8PSA

a.

To determine

To Evaluate: The value of AB¯

a.

Expert Solution
Check Mark

Answer to Problem 8PSA

  AB¯=4units

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.5, Problem 8PSA , additional homework tip  1

B and C are trisection point of AD¯ , where AD¯=12

Concept Used:

Trisected points divides the line segment in three equal parts.

Calculation:

As here, B and C are trisection point of AD¯ , where AD¯=12

  AB¯=BC¯=CD¯=13×AD¯=13×12=4AB¯=4units

Conclusion:

  AB¯=4units

b.

To determine

To Evaluate: The value of AB¯

b.

Expert Solution
Check Mark

Answer to Problem 8PSA

  AC¯=8units

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.5, Problem 8PSA , additional homework tip  2

B and C are trisection point of AD¯ , where AD¯=12

Concept Used:

Trisected points divides the line segment in three equal parts.

Calculation:

As here, B and C are trisection point of AD¯ , where AD¯=12

  AB¯=BC¯=CD¯=13×AD¯=13×12=4AC¯=AB¯+BC¯=4units + 4units = 8unitsAC¯=8units

Conclusion:

  AC¯=8units

c.

To determine

To Find: The value of x

c.

Expert Solution
Check Mark

Answer to Problem 8PSA

  x=1

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.5, Problem 8PSA , additional homework tip  3

B and C are trisection point of AD¯ , where AD¯=12 and AB¯=x+3

Concept Used:

Trisected points divides the line segment in three equal parts.

Calculation:

As here, B and C are trisection point of AD¯ , where AD¯=12

  AB¯=BC¯=CD¯=13×AD¯=13×12=4Also AB¯=x+34=x+3x=1

Conclusion:

  x=1

d.

To determine

To Find: The value of AE¯ .

d.

Expert Solution
Check Mark

Answer to Problem 8PSA

  AE¯=9units

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.5, Problem 8PSA , additional homework tip  4

B and C are trisection point of AD¯ , where AD¯=12

  AB¯=x+3andAE¯=3x+6

Concept Used:

Trisected points divides the line segment in three equal parts.

Calculation:

As here, B and C are trisection point of AD¯ , where AD¯=12

  AB¯=BC¯=CD¯=13×AD¯=13×12=4Also AB¯=x+34=x+3x=1AE¯=3×1+6=9units

Conclusion:

  AE¯=9units

e.

To determine

To Find: The segment for which the point C is the mid-point.

e.

Expert Solution
Check Mark

Answer to Problem 8PSA

  BD

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.5, Problem 8PSA , additional homework tip  5

B and C are trisection point of AD¯ , where AD¯=12

Concept Used:

Trisected points divides the line segment in three equal parts.

Calculation:

As here, B and C are trisection point of AD¯ , where AD¯=12

  AB¯=BC¯=CD¯=13×AD¯=13×12=4BC¯=CD¯=4unitsC is the mid-point of the segment BD.

Conclusion:

  C is the mid-point of the segment BD.

f.

To determine

To Find: Whether the EB and ECtrisect AED ?

f.

Expert Solution
Check Mark

Answer to Problem 8PSA

  Yes, the EB and ECtrisect AED.

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.5, Problem 8PSA , additional homework tip  6

B and C are trisection point of AD¯ , where AD¯=12

Concept Used:

Trisected points divides the line segment in three equal parts.

Calculation:

As here, B and C are trisection point of AD¯ , where AD¯=12

  AB¯=BC¯=CD¯=13×AD¯=13×12=4unitsB is the mid-point of the segment AC.C is the mid-point of the segment BD.

Line joining the points B and C trisect the angle AED

  Thus, the EB and ECtrisect AED.

Conclusion:

  Thus, the EB and ECtrisect AED.

Chapter 1 Solutions

Geometry For Enjoyment And Challenge

Ch. 1.1 - Prob. 11PSBCh. 1.1 - Prob. 12PSBCh. 1.1 - Prob. 13PSCCh. 1.1 - Prob. 14PSCCh. 1.2 - Prob. 1PSACh. 1.2 - Prob. 2PSACh. 1.2 - Prob. 3PSACh. 1.2 - Prob. 4PSACh. 1.2 - Prob. 5PSACh. 1.2 - Prob. 6PSACh. 1.2 - Prob. 7PSACh. 1.2 - Prob. 8PSACh. 1.2 - Prob. 9PSACh. 1.2 - Prob. 10PSACh. 1.2 - Prob. 11PSACh. 1.2 - Prob. 12PSBCh. 1.2 - Prob. 13PSBCh. 1.2 - Prob. 14PSBCh. 1.2 - Prob. 15PSBCh. 1.2 - Prob. 16PSBCh. 1.2 - Prob. 17PSBCh. 1.2 - Prob. 18PSBCh. 1.2 - Prob. 19PSCCh. 1.2 - Prob. 20PSCCh. 1.2 - Prob. 21PSCCh. 1.2 - Prob. 22PSCCh. 1.2 - Prob. 23PSCCh. 1.3 - Prob. 1PSACh. 1.3 - Prob. 2PSACh. 1.3 - Prob. 3PSACh. 1.3 - Prob. 4PSACh. 1.3 - Prob. 5PSACh. 1.3 - Prob. 6PSACh. 1.3 - Prob. 7PSACh. 1.3 - Prob. 8PSACh. 1.3 - Prob. 9PSACh. 1.3 - Prob. 10PSBCh. 1.3 - Prob. 11PSBCh. 1.3 - Prob. 12PSBCh. 1.3 - Prob. 13PSBCh. 1.3 - Prob. 14PSBCh. 1.3 - Prob. 15PSCCh. 1.3 - Prob. 16PSCCh. 1.3 - Prob. 17PSCCh. 1.4 - Prob. 1PSACh. 1.4 - Prob. 2PSACh. 1.4 - Prob. 3PSACh. 1.4 - Prob. 4PSACh. 1.4 - Prob. 5PSACh. 1.4 - Prob. 6PSACh. 1.4 - Prob. 7PSACh. 1.4 - Prob. 8PSACh. 1.4 - Prob. 9PSACh. 1.4 - Prob. 10PSACh. 1.4 - Prob. 11PSBCh. 1.4 - Prob. 12PSBCh. 1.4 - Prob. 13PSBCh. 1.4 - Prob. 14PSCCh. 1.4 - Prob. 15PSCCh. 1.5 - Prob. 1PSACh. 1.5 - Prob. 2PSACh. 1.5 - Prob. 3PSACh. 1.5 - Prob. 4PSACh. 1.5 - Prob. 5PSACh. 1.5 - Prob. 6PSACh. 1.5 - Prob. 7PSACh. 1.5 - Prob. 8PSACh. 1.5 - Prob. 9PSACh. 1.5 - Prob. 10PSACh. 1.5 - Prob. 11PSACh. 1.5 - Prob. 12PSACh. 1.5 - Prob. 13PSACh. 1.5 - Prob. 14PSACh. 1.5 - Prob. 15PSACh. 1.5 - Prob. 16PSACh. 1.5 - Prob. 17PSACh. 1.5 - Prob. 18PSBCh. 1.5 - Prob. 19PSBCh. 1.5 - Prob. 20PSBCh. 1.5 - Prob. 21PSBCh. 1.5 - Prob. 22PSCCh. 1.5 - Prob. 23PSCCh. 1.5 - Prob. 24PSCCh. 1.6 - Prob. 1PSACh. 1.6 - Prob. 2PSACh. 1.6 - Prob. 3PSACh. 1.6 - Prob. 4PSACh. 1.6 - Prob. 5PSACh. 1.6 - Prob. 6PSACh. 1.6 - Prob. 7PSBCh. 1.6 - Prob. 8PSBCh. 1.6 - Prob. 9PSBCh. 1.6 - Prob. 10PSCCh. 1.6 - Prob. 11PSCCh. 1.6 - Prob. 12PSDCh. 1.7 - Prob. 1PSACh. 1.7 - Prob. 2PSACh. 1.7 - Prob. 3PSACh. 1.7 - Prob. 4PSACh. 1.7 - Prob. 5PSACh. 1.7 - Prob. 6PSACh. 1.7 - Prob. 7PSACh. 1.7 - Prob. 8PSBCh. 1.7 - Prob. 9PSBCh. 1.7 - Prob. 10PSBCh. 1.7 - Prob. 11PSBCh. 1.7 - Prob. 12PSBCh. 1.7 - Prob. 13PSCCh. 1.7 - Prob. 14PSCCh. 1.8 - Prob. 1PSACh. 1.8 - Prob. 2PSACh. 1.8 - Prob. 3PSACh. 1.8 - Prob. 4PSACh. 1.8 - Prob. 5PSACh. 1.8 - Prob. 6PSBCh. 1.8 - Prob. 7PSBCh. 1.8 - Prob. 8PSBCh. 1.8 - Prob. 9PSBCh. 1.8 - Prob. 10PSCCh. 1.9 - Prob. 1PSACh. 1.9 - Prob. 2PSACh. 1.9 - Prob. 3PSACh. 1.9 - Prob. 4PSACh. 1.9 - Prob. 5PSACh. 1.9 - Prob. 6PSBCh. 1.9 - Prob. 7PSBCh. 1.9 - Prob. 8PSBCh. 1.9 - Prob. 9PSBCh. 1.9 - Prob. 10PSBCh. 1.9 - Prob. 11PSBCh. 1.9 - Prob. 12PSCCh. 1.9 - Prob. 13PSCCh. 1.9 - Prob. 14PSCCh. 1.9 - Prob. 15PSCCh. 1 - Prob. 1RPCh. 1 - Prob. 2RPCh. 1 - Prob. 3RPCh. 1 - Prob. 4RPCh. 1 - Prob. 5RPCh. 1 - Prob. 6RPCh. 1 - Prob. 7RPCh. 1 - Prob. 8RPCh. 1 - Prob. 9RPCh. 1 - Prob. 10RPCh. 1 - Prob. 11RPCh. 1 - Prob. 12RPCh. 1 - Prob. 13RPCh. 1 - Prob. 14RPCh. 1 - Prob. 15RPCh. 1 - Prob. 16RPCh. 1 - Prob. 17RPCh. 1 - Prob. 18RPCh. 1 - Prob. 19RPCh. 1 - Prob. 20RPCh. 1 - Prob. 21RPCh. 1 - Prob. 22RPCh. 1 - Prob. 23RPCh. 1 - Prob. 24RPCh. 1 - Prob. 25RPCh. 1 - Prob. 26RPCh. 1 - Prob. 27RPCh. 1 - Prob. 28RPCh. 1 - Prob. 29RPCh. 1 - Prob. 30RPCh. 1 - Prob. 31RPCh. 1 - Prob. 32RPCh. 1 - Prob. 33RPCh. 1 - Prob. 34RPCh. 1 - Prob. 35RPCh. 1 - Prob. 36RPCh. 1 - Prob. 37RPCh. 1 - Prob. 38RPCh. 1 - Prob. 39RPCh. 1 - Prob. 40RPCh. 1 - Prob. 41RPCh. 1 - Prob. 42RPCh. 1 - Prob. 43RP

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