Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Question
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Chapter 1.2, Problem 12PSB

a.

To determine

To find: The number of triangles in the given figure.

a.

Expert Solution
Check Mark

Answer to Problem 12PSB

There are eight triangles in the given figure.

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.2, Problem 12PSB , additional homework tip  1

A parallelogram ABCD having diagonals AC and BD intersecting at E.

Concept Used:

Triangle is a three sided closed polygon.

Calculation:

Here, we have a parallelogram ABCD having diagonals AC and BD intersecting at E shown as

  Geometry For Enjoyment And Challenge, Chapter 1.2, Problem 12PSB , additional homework tip  2

As we know that Triangle is a three sided closed polygon.

The triangles in the given figure are

  AED,EDC,ECB,EBA,ADC,DCB,CBA,ABD

Thus, there are eight triangles in the given figure.

Conclusion:

There are eight triangles in the given figure.

b.

To determine

To find: The number of angles in the given figure.

b.

Expert Solution
Check Mark

Answer to Problem 12PSB

There are 12 angles in the given figure.

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.2, Problem 12PSB , additional homework tip  3

A parallelogram ABCD having diagonals AC and BD intersecting at E.

Concept Used:

Two lines passing through a single point known as vertex forms an angle.

Calculation:

Here, we have a parallelogram ABCD having diagonals AC and BD intersecting at E shown as

  Geometry For Enjoyment And Challenge, Chapter 1.2, Problem 12PSB , additional homework tip  4

As we know that angle is formed when two lines passing through a single point known as vertex.

Angles in the given figure are

  EAD,AED,ADE,EDC,DEC,ECD,ECB,BEC,CBE,EAB,AEB,ABE

Thus, there are 12 angles in the given figure.

Conclusion:

There are 12 angles in the given figure.

c.

To determine

To find: The number of angles appears to be acute angle in the given figure.

c.

Expert Solution
Check Mark

Answer to Problem 12PSB

There are 6 acute angles in the given figure.

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.2, Problem 12PSB , additional homework tip  5

A parallelogram ABCD having diagonals AC and BD intersecting at E.

Concept Used:

Two lines passing through a single point known as vertex forms an angle. Acute angle is the angle whose measure is greater than zero degree but less than 90 degrees.

Calculation:

Here, we have a parallelogram ABCD having diagonals AC and BD intersecting at E shown as

  Geometry For Enjoyment And Challenge, Chapter 1.2, Problem 12PSB , additional homework tip  6

As we know that angle is formed when two lines passing through a single point known as vertex.

Acute angles in the given figure are

  EAD,ADE,EDC,ECD,ECB,CBE,EAB,ABE

Thus, there are 6 acute angles in the given figure.

Conclusion:

There are 6 acute angles in the given figure.

d.

To determine

To find: The number of angles appears to be obtuse angle in the given figure.

d.

Expert Solution
Check Mark

Answer to Problem 12PSB

There are 4 obtuse angles in the given figure.

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.2, Problem 12PSB , additional homework tip  7

A parallelogram ABCD having diagonals AC and BD intersecting at E.

Concept Used:

Two lines passing through a single point known as vertex forms an angle. Obtuse angle is the angle whose measure is greater than 90 degrees but less than 180 degrees.

Calculation:

Here, we have a parallelogram ABCD having diagonals AC and BD intersecting at E shown as

  Geometry For Enjoyment And Challenge, Chapter 1.2, Problem 12PSB , additional homework tip  8

As we know that angle is formed when two lines passing through a single point known as vertex.

Obtuse angles in the given figure are

  AED,DEC,BEC,AEB

Thus, there are 4 obtuse angles in the given figure.

Conclusion:

There are 4 obtuse angles in the given figure.

e.

To determine

To find: The straight angles angle in the given figure.

e.

Expert Solution
Check Mark

Answer to Problem 12PSB

  AEC andDEB are the straight angles in the given figure.

Explanation of Solution

Given:

  Geometry For Enjoyment And Challenge, Chapter 1.2, Problem 12PSB , additional homework tip  9

A parallelogram ABCD having diagonals AC and BD intersecting at E.

Concept Used:

Two lines passing through a single point known as vertex forms an angle. Straight angle is the angle whose measure is equal to 180 degrees.

Calculation:

Here, we have a parallelogram ABCD having diagonals AC and BD intersecting at E shown as

  Geometry For Enjoyment And Challenge, Chapter 1.2, Problem 12PSB , additional homework tip  10

As we know that angle is formed when two lines passing through a single point known as vertex.

Straight angles in the given figure formed using the given diagonal, thus the straight angles are

  AEC andDEB

Thus, there are two straight angles in the given figure.

Conclusion:

  AEC andDEB are the straight angles in the given figure.

Chapter 1 Solutions

Geometry For Enjoyment And Challenge

Ch. 1.1 - Prob. 11PSBCh. 1.1 - Prob. 12PSBCh. 1.1 - Prob. 13PSCCh. 1.1 - Prob. 14PSCCh. 1.2 - Prob. 1PSACh. 1.2 - Prob. 2PSACh. 1.2 - Prob. 3PSACh. 1.2 - Prob. 4PSACh. 1.2 - Prob. 5PSACh. 1.2 - Prob. 6PSACh. 1.2 - Prob. 7PSACh. 1.2 - Prob. 8PSACh. 1.2 - Prob. 9PSACh. 1.2 - Prob. 10PSACh. 1.2 - Prob. 11PSACh. 1.2 - Prob. 12PSBCh. 1.2 - Prob. 13PSBCh. 1.2 - Prob. 14PSBCh. 1.2 - Prob. 15PSBCh. 1.2 - Prob. 16PSBCh. 1.2 - Prob. 17PSBCh. 1.2 - Prob. 18PSBCh. 1.2 - Prob. 19PSCCh. 1.2 - Prob. 20PSCCh. 1.2 - Prob. 21PSCCh. 1.2 - Prob. 22PSCCh. 1.2 - Prob. 23PSCCh. 1.3 - Prob. 1PSACh. 1.3 - Prob. 2PSACh. 1.3 - Prob. 3PSACh. 1.3 - Prob. 4PSACh. 1.3 - Prob. 5PSACh. 1.3 - Prob. 6PSACh. 1.3 - Prob. 7PSACh. 1.3 - Prob. 8PSACh. 1.3 - Prob. 9PSACh. 1.3 - Prob. 10PSBCh. 1.3 - Prob. 11PSBCh. 1.3 - Prob. 12PSBCh. 1.3 - Prob. 13PSBCh. 1.3 - Prob. 14PSBCh. 1.3 - Prob. 15PSCCh. 1.3 - Prob. 16PSCCh. 1.3 - Prob. 17PSCCh. 1.4 - Prob. 1PSACh. 1.4 - Prob. 2PSACh. 1.4 - Prob. 3PSACh. 1.4 - Prob. 4PSACh. 1.4 - Prob. 5PSACh. 1.4 - Prob. 6PSACh. 1.4 - Prob. 7PSACh. 1.4 - Prob. 8PSACh. 1.4 - Prob. 9PSACh. 1.4 - Prob. 10PSACh. 1.4 - Prob. 11PSBCh. 1.4 - Prob. 12PSBCh. 1.4 - Prob. 13PSBCh. 1.4 - Prob. 14PSCCh. 1.4 - Prob. 15PSCCh. 1.5 - Prob. 1PSACh. 1.5 - Prob. 2PSACh. 1.5 - Prob. 3PSACh. 1.5 - Prob. 4PSACh. 1.5 - Prob. 5PSACh. 1.5 - Prob. 6PSACh. 1.5 - Prob. 7PSACh. 1.5 - Prob. 8PSACh. 1.5 - Prob. 9PSACh. 1.5 - Prob. 10PSACh. 1.5 - Prob. 11PSACh. 1.5 - Prob. 12PSACh. 1.5 - Prob. 13PSACh. 1.5 - Prob. 14PSACh. 1.5 - Prob. 15PSACh. 1.5 - Prob. 16PSACh. 1.5 - Prob. 17PSACh. 1.5 - Prob. 18PSBCh. 1.5 - Prob. 19PSBCh. 1.5 - Prob. 20PSBCh. 1.5 - Prob. 21PSBCh. 1.5 - Prob. 22PSCCh. 1.5 - Prob. 23PSCCh. 1.5 - Prob. 24PSCCh. 1.6 - Prob. 1PSACh. 1.6 - Prob. 2PSACh. 1.6 - Prob. 3PSACh. 1.6 - Prob. 4PSACh. 1.6 - Prob. 5PSACh. 1.6 - Prob. 6PSACh. 1.6 - Prob. 7PSBCh. 1.6 - Prob. 8PSBCh. 1.6 - Prob. 9PSBCh. 1.6 - Prob. 10PSCCh. 1.6 - Prob. 11PSCCh. 1.6 - Prob. 12PSDCh. 1.7 - Prob. 1PSACh. 1.7 - Prob. 2PSACh. 1.7 - Prob. 3PSACh. 1.7 - Prob. 4PSACh. 1.7 - Prob. 5PSACh. 1.7 - Prob. 6PSACh. 1.7 - Prob. 7PSACh. 1.7 - Prob. 8PSBCh. 1.7 - Prob. 9PSBCh. 1.7 - Prob. 10PSBCh. 1.7 - Prob. 11PSBCh. 1.7 - Prob. 12PSBCh. 1.7 - Prob. 13PSCCh. 1.7 - Prob. 14PSCCh. 1.8 - Prob. 1PSACh. 1.8 - Prob. 2PSACh. 1.8 - Prob. 3PSACh. 1.8 - Prob. 4PSACh. 1.8 - Prob. 5PSACh. 1.8 - Prob. 6PSBCh. 1.8 - Prob. 7PSBCh. 1.8 - Prob. 8PSBCh. 1.8 - Prob. 9PSBCh. 1.8 - Prob. 10PSCCh. 1.9 - Prob. 1PSACh. 1.9 - Prob. 2PSACh. 1.9 - Prob. 3PSACh. 1.9 - Prob. 4PSACh. 1.9 - Prob. 5PSACh. 1.9 - Prob. 6PSBCh. 1.9 - Prob. 7PSBCh. 1.9 - Prob. 8PSBCh. 1.9 - Prob. 9PSBCh. 1.9 - Prob. 10PSBCh. 1.9 - Prob. 11PSBCh. 1.9 - Prob. 12PSCCh. 1.9 - Prob. 13PSCCh. 1.9 - Prob. 14PSCCh. 1.9 - Prob. 15PSCCh. 1 - Prob. 1RPCh. 1 - Prob. 2RPCh. 1 - Prob. 3RPCh. 1 - Prob. 4RPCh. 1 - Prob. 5RPCh. 1 - Prob. 6RPCh. 1 - Prob. 7RPCh. 1 - Prob. 8RPCh. 1 - Prob. 9RPCh. 1 - Prob. 10RPCh. 1 - Prob. 11RPCh. 1 - Prob. 12RPCh. 1 - Prob. 13RPCh. 1 - Prob. 14RPCh. 1 - Prob. 15RPCh. 1 - Prob. 16RPCh. 1 - Prob. 17RPCh. 1 - Prob. 18RPCh. 1 - Prob. 19RPCh. 1 - Prob. 20RPCh. 1 - Prob. 21RPCh. 1 - Prob. 22RPCh. 1 - Prob. 23RPCh. 1 - Prob. 24RPCh. 1 - Prob. 25RPCh. 1 - Prob. 26RPCh. 1 - Prob. 27RPCh. 1 - Prob. 28RPCh. 1 - Prob. 29RPCh. 1 - Prob. 30RPCh. 1 - Prob. 31RPCh. 1 - Prob. 32RPCh. 1 - Prob. 33RPCh. 1 - Prob. 34RPCh. 1 - Prob. 35RPCh. 1 - Prob. 36RPCh. 1 - Prob. 37RPCh. 1 - Prob. 38RPCh. 1 - Prob. 39RPCh. 1 - Prob. 40RPCh. 1 - Prob. 41RPCh. 1 - Prob. 42RPCh. 1 - Prob. 43RP
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