Chapter 1.5, Problem 16PSA

To determine

To Prove: $\angle TXW\cong \angle TYV$

Explanation of Solution

Given:

  

  $\begin{array}{l}\angle TXW\text{is a right angle}\\ \angle TYV\text{is a right angle}\end{array}$

Concept Used:

Angles of equal measure are congruent.

Proof:

Here, we have

  $\begin{array}{l}\angle TXW\text{is a right angle}\\ \Rightarrow m\angle TXW=90°\\ \angle TYV\text{is a right angle}\\ \Rightarrow m\angle TYV=90°\\ \Rightarrow \angle TXW\cong \angle TYV\end{array}$