Chapter 1.4, Problem 3PSA

To determine

To Show: $\angle A\cong \angle B$

Explanation of Solution

Given information :

  $\begin{array}{l}\angle A\text{ is a right angle}\text{.}\\ \angle B\text{ is a right angle}\text{.}\end{array}$

  

Proof:

Here, we have

  $\begin{array}{l}\angle A\text{ is a right angle}\text{.}\\ \angle B\text{ is a right angle}\text{.}\\ \Rightarrow \angle A=90°\\ \Rightarrow \angle B=90°\\ \Rightarrow \angle A=\angle B=90°\end{array}$

  $\text{Thus,}\angle A\cong \angle B$