Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Chapter 1, Problem 31RP

a )

To determine

To Find : The measure of angle ABD to the nearest tenth of a degree

a )

Expert Solution
Check Mark

Answer to Problem 31RP

The measure of angle ABD to the nearest tenth of a degree = 44.5°

Explanation of Solution

Given: In the given figure on line AC two adjacent angles ABD=(812x)° , DBC = (2469x)° are marked

Concept Used: Two adjacent angles standing on a straight line form a linear pair which means they add up to 180°

Calculation: As per the given figure ABD , DBC form a linear pair. So,

  ABD + DBC = 180°  also ABD=(812x)° , DBC = (2469x)° .Which means:

  ABD + DBC = 180°(812x)°+ ( 2469x)° = 180° (3281x)° = 180°x = (180°3281°)x = 0.05486

(Taking value up to 5 decimal places)

So,  ABD = (812x)° ABD = (812 × 0.05486)° = 44.54632°

Converting this value to the nearest tenth place we will get 44.54632° = 44.5°

Conclusion:

The measure of angle ABD to the nearest tenth of a degree = 44.5°

b)

To determine

To Find: The measure of given angle to its nearest minute

b)

Expert Solution
Check Mark

Answer to Problem 31RP

The measure of given angle to its nearest minute = 44° 33 '

Explanation of Solution

Given: In the given figure on line AC two adjacent angles ABD=(812x)° , DBC = (2469x)° are marked

Concept Used: Two adjacent angles standing on a straight line form a linear pair which means they add up to 180°

Calculation: As per the given figure ABD , DBC form a linear pair. So,

  ABD + DBC = 180°  also ABD=(812x)° , DBC = (2469x)° .Which means:

  ABD + DBC = 180°(812x)°+ ( 2469x)° = 180° (3281x)° = 180°x = (180°3281°)x = 0.05486

(Taking value up to 5 decimal places)

So,  ABD = (812x)° ABD = (812 × 0.05486)° = 44.54632°

Converting 44.54632° into minutes by multiplying decimal part by 60

  0.54632 ° × 60 = 32.7792 minutes

Writing it to the nearest minute we will get : 44° 33 '

Conclusion:

The measure of given angle to its nearest minute = 44° 33 '

Chapter 1 Solutions

Geometry For Enjoyment And Challenge

Ch. 1.1 - Prob. 11PSBCh. 1.1 - Prob. 12PSBCh. 1.1 - Prob. 13PSCCh. 1.1 - Prob. 14PSCCh. 1.2 - Prob. 1PSACh. 1.2 - Prob. 2PSACh. 1.2 - Prob. 3PSACh. 1.2 - Prob. 4PSACh. 1.2 - Prob. 5PSACh. 1.2 - Prob. 6PSACh. 1.2 - Prob. 7PSACh. 1.2 - Prob. 8PSACh. 1.2 - Prob. 9PSACh. 1.2 - Prob. 10PSACh. 1.2 - Prob. 11PSACh. 1.2 - Prob. 12PSBCh. 1.2 - Prob. 13PSBCh. 1.2 - Prob. 14PSBCh. 1.2 - Prob. 15PSBCh. 1.2 - Prob. 16PSBCh. 1.2 - Prob. 17PSBCh. 1.2 - Prob. 18PSBCh. 1.2 - Prob. 19PSCCh. 1.2 - Prob. 20PSCCh. 1.2 - Prob. 21PSCCh. 1.2 - Prob. 22PSCCh. 1.2 - Prob. 23PSCCh. 1.3 - Prob. 1PSACh. 1.3 - Prob. 2PSACh. 1.3 - Prob. 3PSACh. 1.3 - Prob. 4PSACh. 1.3 - Prob. 5PSACh. 1.3 - Prob. 6PSACh. 1.3 - Prob. 7PSACh. 1.3 - Prob. 8PSACh. 1.3 - Prob. 9PSACh. 1.3 - Prob. 10PSBCh. 1.3 - Prob. 11PSBCh. 1.3 - Prob. 12PSBCh. 1.3 - Prob. 13PSBCh. 1.3 - Prob. 14PSBCh. 1.3 - Prob. 15PSCCh. 1.3 - Prob. 16PSCCh. 1.3 - Prob. 17PSCCh. 1.4 - Prob. 1PSACh. 1.4 - Prob. 2PSACh. 1.4 - Prob. 3PSACh. 1.4 - Prob. 4PSACh. 1.4 - Prob. 5PSACh. 1.4 - Prob. 6PSACh. 1.4 - Prob. 7PSACh. 1.4 - Prob. 8PSACh. 1.4 - Prob. 9PSACh. 1.4 - Prob. 10PSACh. 1.4 - Prob. 11PSBCh. 1.4 - Prob. 12PSBCh. 1.4 - Prob. 13PSBCh. 1.4 - Prob. 14PSCCh. 1.4 - Prob. 15PSCCh. 1.5 - Prob. 1PSACh. 1.5 - Prob. 2PSACh. 1.5 - Prob. 3PSACh. 1.5 - Prob. 4PSACh. 1.5 - Prob. 5PSACh. 1.5 - Prob. 6PSACh. 1.5 - Prob. 7PSACh. 1.5 - Prob. 8PSACh. 1.5 - Prob. 9PSACh. 1.5 - Prob. 10PSACh. 1.5 - Prob. 11PSACh. 1.5 - Prob. 12PSACh. 1.5 - Prob. 13PSACh. 1.5 - Prob. 14PSACh. 1.5 - Prob. 15PSACh. 1.5 - Prob. 16PSACh. 1.5 - Prob. 17PSACh. 1.5 - Prob. 18PSBCh. 1.5 - Prob. 19PSBCh. 1.5 - Prob. 20PSBCh. 1.5 - Prob. 21PSBCh. 1.5 - Prob. 22PSCCh. 1.5 - Prob. 23PSCCh. 1.5 - Prob. 24PSCCh. 1.6 - Prob. 1PSACh. 1.6 - Prob. 2PSACh. 1.6 - Prob. 3PSACh. 1.6 - Prob. 4PSACh. 1.6 - Prob. 5PSACh. 1.6 - Prob. 6PSACh. 1.6 - Prob. 7PSBCh. 1.6 - Prob. 8PSBCh. 1.6 - Prob. 9PSBCh. 1.6 - Prob. 10PSCCh. 1.6 - Prob. 11PSCCh. 1.6 - Prob. 12PSDCh. 1.7 - Prob. 1PSACh. 1.7 - Prob. 2PSACh. 1.7 - Prob. 3PSACh. 1.7 - Prob. 4PSACh. 1.7 - Prob. 5PSACh. 1.7 - Prob. 6PSACh. 1.7 - Prob. 7PSACh. 1.7 - Prob. 8PSBCh. 1.7 - Prob. 9PSBCh. 1.7 - Prob. 10PSBCh. 1.7 - Prob. 11PSBCh. 1.7 - Prob. 12PSBCh. 1.7 - Prob. 13PSCCh. 1.7 - Prob. 14PSCCh. 1.8 - Prob. 1PSACh. 1.8 - Prob. 2PSACh. 1.8 - Prob. 3PSACh. 1.8 - Prob. 4PSACh. 1.8 - Prob. 5PSACh. 1.8 - Prob. 6PSBCh. 1.8 - Prob. 7PSBCh. 1.8 - Prob. 8PSBCh. 1.8 - Prob. 9PSBCh. 1.8 - Prob. 10PSCCh. 1.9 - Prob. 1PSACh. 1.9 - Prob. 2PSACh. 1.9 - Prob. 3PSACh. 1.9 - Prob. 4PSACh. 1.9 - Prob. 5PSACh. 1.9 - Prob. 6PSBCh. 1.9 - Prob. 7PSBCh. 1.9 - Prob. 8PSBCh. 1.9 - Prob. 9PSBCh. 1.9 - Prob. 10PSBCh. 1.9 - Prob. 11PSBCh. 1.9 - Prob. 12PSCCh. 1.9 - Prob. 13PSCCh. 1.9 - Prob. 14PSCCh. 1.9 - Prob. 15PSCCh. 1 - Prob. 1RPCh. 1 - Prob. 2RPCh. 1 - Prob. 3RPCh. 1 - Prob. 4RPCh. 1 - Prob. 5RPCh. 1 - Prob. 6RPCh. 1 - Prob. 7RPCh. 1 - Prob. 8RPCh. 1 - Prob. 9RPCh. 1 - Prob. 10RPCh. 1 - Prob. 11RPCh. 1 - Prob. 12RPCh. 1 - Prob. 13RPCh. 1 - Prob. 14RPCh. 1 - Prob. 15RPCh. 1 - Prob. 16RPCh. 1 - Prob. 17RPCh. 1 - Prob. 18RPCh. 1 - Prob. 19RPCh. 1 - Prob. 20RPCh. 1 - Prob. 21RPCh. 1 - Prob. 22RPCh. 1 - Prob. 23RPCh. 1 - Prob. 24RPCh. 1 - Prob. 25RPCh. 1 - Prob. 26RPCh. 1 - Prob. 27RPCh. 1 - Prob. 28RPCh. 1 - Prob. 29RPCh. 1 - Prob. 30RPCh. 1 - Prob. 31RPCh. 1 - Prob. 32RPCh. 1 - Prob. 33RPCh. 1 - Prob. 34RPCh. 1 - Prob. 35RPCh. 1 - Prob. 36RPCh. 1 - Prob. 37RPCh. 1 - Prob. 38RPCh. 1 - Prob. 39RPCh. 1 - Prob. 40RPCh. 1 - Prob. 41RPCh. 1 - Prob. 42RPCh. 1 - Prob. 43RP
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