Chapter 1.4, Problem 10PSA

a.

To determine

To Find: The value of $x$ .

Answer to Problem 10PSA

  $x=7.5$

Explanation of Solution

Given:

  

A square of perimeter > 42 units

  $\text{Side of Square}=x+3$

Concept Used:

  $\text{Perimeter of square = 4}\times \left(\text{Side of Square}\right)$

Calculation:

As per the given problem

  $\text{Side of Square}=x+3$

  $\begin{array}{l}\because \text{Perimeter of square = 4}\times \left(\text{Side of Square}\right)=\text{ 42 units}\\ \Rightarrow \text{Perimeter of square = 4}\times \left(x+3\right)=4x+12\text{units}\\ \Rightarrow 4x+12=42\\ \Rightarrow 4x=30\\ \Rightarrow x=7.5\end{array}$

Conclusion:

  $x=7.5$

b.

To determine

To Find: The value of $x$ .

Answer to Problem 10PSA

  $x>7.5$

Explanation of Solution

Given:

  

A square of perimeter = 42 units

  $\text{Side of Square}=x+3$

Concept Used:

  $\text{Perimeter of square = 4}\times \left(\text{Side of Square}\right)$

Calculation:

As per the given problem

  $\text{Side of Square}=x+3$

  $\begin{array}{l}\because \text{Perimeter of square = 4}\times \left(\text{Side of Square}\right)>\text{ 42 units}\\ \Rightarrow \text{Perimeter of square = 4}\times \left(x+3\right)=4x+12\text{units}\\ \Rightarrow 4x+12>42\\ \Rightarrow 4x>30\\ \Rightarrow x>7.5\end{array}$

Conclusion:

  $x>7.5$