The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.

Question

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Answer 1

Question

Chapter 18, Problem 1TYK

Summary Introduction

Introduction:

The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.

Expert Solution & Answer

Answer to Problem 1TYK

Correct answer:

The sequence of nucleotides.

Explanation of Solution

Justification/ Explanation for the correct answer:

Option (a) is the sequence of nucleotides. The restriction enzymes help in recognition of restriction sites on the DNA fragments and cut them into different fragments. These restriction sites contain sequences of nucleotides that are recognized by enzymes and are palindromic in nature. There is a number of restriction enzymes identified for cutting DNA at specific restriction sites. Hence, option (a) is correct.

The explanation for the incorrect answers:

Option (b) is the length of DNA molecule. The activity of restriction enzymes depends on the presence of restriction sites on the DNA molecule. A long DNA molecule cannot be cut by an enzyme, if it does not contain particular recognition sites. So, it is an incorrect option.

Option (c) is whether it is closer to 5’end or 3´end of DNA molecule. The restriction enzymes recognize the palindromic sequence of DNA sequences, which can be read in both sides, from 5’ to 3´ and 3´ to 5´ ends. So, it is an incorrect option.

Option (d) is the number of copies of DNA molecule in a bacterial cell. A large number of copies of DNA cannot be cleaved by restriction enzymes without any restriction sites. So, it is an incorrect option.

Option (e) is the location of a start codon in a gene. Start codon only helps in the initiation of translation and protein synthesis. So, it is an incorrect option.

Hence, options (b), (c), (d) and (e) are incorrect.

Conclusion

Restriction sites are the sequence of DNA fragments which may vary in number and are recognized by a specific restriction endonuclease. The enzyme endonuclease cleaves the DNA fragment generating small fragments with sticky ends or blunt ends.

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Answer 2

Question

Chapter 18, Problem 1TYK

Summary Introduction

Introduction:

The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.

Expert Solution & Answer

Answer to Problem 1TYK

Correct answer:

The sequence of nucleotides.

Explanation of Solution

Justification/ Explanation for the correct answer:

Option (a) is the sequence of nucleotides. The restriction enzymes help in recognition of restriction sites on the DNA fragments and cut them into different fragments. These restriction sites contain sequences of nucleotides that are recognized by enzymes and are palindromic in nature. There is a number of restriction enzymes identified for cutting DNA at specific restriction sites. Hence, option (a) is correct.

The explanation for the incorrect answers:

Option (b) is the length of DNA molecule. The activity of restriction enzymes depends on the presence of restriction sites on the DNA molecule. A long DNA molecule cannot be cut by an enzyme, if it does not contain particular recognition sites. So, it is an incorrect option.

Option (c) is whether it is closer to 5’end or 3´end of DNA molecule. The restriction enzymes recognize the palindromic sequence of DNA sequences, which can be read in both sides, from 5’ to 3´ and 3´ to 5´ ends. So, it is an incorrect option.

Option (d) is the number of copies of DNA molecule in a bacterial cell. A large number of copies of DNA cannot be cleaved by restriction enzymes without any restriction sites. So, it is an incorrect option.

Option (e) is the location of a start codon in a gene. Start codon only helps in the initiation of translation and protein synthesis. So, it is an incorrect option.

Hence, options (b), (c), (d) and (e) are incorrect.

Conclusion

Restriction sites are the sequence of DNA fragments which may vary in number and are recognized by a specific restriction endonuclease. The enzyme endonuclease cleaves the DNA fragment generating small fragments with sticky ends or blunt ends.

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Answer 3

Question

Chapter 18, Problem 1TYK

Summary Introduction

Introduction:

The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.

Expert Solution & Answer

Answer to Problem 1TYK

Correct answer:

The sequence of nucleotides.

Explanation of Solution

Justification/ Explanation for the correct answer:

Option (a) is the sequence of nucleotides. The restriction enzymes help in recognition of restriction sites on the DNA fragments and cut them into different fragments. These restriction sites contain sequences of nucleotides that are recognized by enzymes and are palindromic in nature. There is a number of restriction enzymes identified for cutting DNA at specific restriction sites. Hence, option (a) is correct.

The explanation for the incorrect answers:

Option (b) is the length of DNA molecule. The activity of restriction enzymes depends on the presence of restriction sites on the DNA molecule. A long DNA molecule cannot be cut by an enzyme, if it does not contain particular recognition sites. So, it is an incorrect option.

Option (c) is whether it is closer to 5’end or 3´end of DNA molecule. The restriction enzymes recognize the palindromic sequence of DNA sequences, which can be read in both sides, from 5’ to 3´ and 3´ to 5´ ends. So, it is an incorrect option.

Option (d) is the number of copies of DNA molecule in a bacterial cell. A large number of copies of DNA cannot be cleaved by restriction enzymes without any restriction sites. So, it is an incorrect option.

Option (e) is the location of a start codon in a gene. Start codon only helps in the initiation of translation and protein synthesis. So, it is an incorrect option.

Hence, options (b), (c), (d) and (e) are incorrect.

Conclusion

Restriction sites are the sequence of DNA fragments which may vary in number and are recognized by a specific restriction endonuclease. The enzyme endonuclease cleaves the DNA fragment generating small fragments with sticky ends or blunt ends.

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Answer 4

Question

Chapter 18, Problem 1TYK

Summary Introduction

Introduction:

The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.

Expert Solution & Answer

Answer to Problem 1TYK

Correct answer:

The sequence of nucleotides.

Explanation of Solution

Justification/ Explanation for the correct answer:

Option (a) is the sequence of nucleotides. The restriction enzymes help in recognition of restriction sites on the DNA fragments and cut them into different fragments. These restriction sites contain sequences of nucleotides that are recognized by enzymes and are palindromic in nature. There is a number of restriction enzymes identified for cutting DNA at specific restriction sites. Hence, option (a) is correct.

The explanation for the incorrect answers:

Option (b) is the length of DNA molecule. The activity of restriction enzymes depends on the presence of restriction sites on the DNA molecule. A long DNA molecule cannot be cut by an enzyme, if it does not contain particular recognition sites. So, it is an incorrect option.

Option (c) is whether it is closer to 5’end or 3´end of DNA molecule. The restriction enzymes recognize the palindromic sequence of DNA sequences, which can be read in both sides, from 5’ to 3´ and 3´ to 5´ ends. So, it is an incorrect option.

Option (d) is the number of copies of DNA molecule in a bacterial cell. A large number of copies of DNA cannot be cleaved by restriction enzymes without any restriction sites. So, it is an incorrect option.

Option (e) is the location of a start codon in a gene. Start codon only helps in the initiation of translation and protein synthesis. So, it is an incorrect option.

Hence, options (b), (c), (d) and (e) are incorrect.

Conclusion

Restriction sites are the sequence of DNA fragments which may vary in number and are recognized by a specific restriction endonuclease. The enzyme endonuclease cleaves the DNA fragment generating small fragments with sticky ends or blunt ends.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 18, Problem 1TYK

Summary Introduction

Introduction:

The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.

Expert Solution & Answer

Answer to Problem 1TYK

Correct answer:

The sequence of nucleotides.

Explanation of Solution

Justification/ Explanation for the correct answer:

Option (a) is the sequence of nucleotides. The restriction enzymes help in recognition of restriction sites on the DNA fragments and cut them into different fragments. These restriction sites contain sequences of nucleotides that are recognized by enzymes and are palindromic in nature. There is a number of restriction enzymes identified for cutting DNA at specific restriction sites. Hence, option (a) is correct.

The explanation for the incorrect answers:

Option (b) is the length of DNA molecule. The activity of restriction enzymes depends on the presence of restriction sites on the DNA molecule. A long DNA molecule cannot be cut by an enzyme, if it does not contain particular recognition sites. So, it is an incorrect option.

Option (c) is whether it is closer to 5’end or 3´end of DNA molecule. The restriction enzymes recognize the palindromic sequence of DNA sequences, which can be read in both sides, from 5’ to 3´ and 3´ to 5´ ends. So, it is an incorrect option.

Option (d) is the number of copies of DNA molecule in a bacterial cell. A large number of copies of DNA cannot be cleaved by restriction enzymes without any restriction sites. So, it is an incorrect option.

Option (e) is the location of a start codon in a gene. Start codon only helps in the initiation of translation and protein synthesis. So, it is an incorrect option.

Hence, options (b), (c), (d) and (e) are incorrect.

Conclusion

Restriction sites are the sequence of DNA fragments which may vary in number and are recognized by a specific restriction endonuclease. The enzyme endonuclease cleaves the DNA fragment generating small fragments with sticky ends or blunt ends.

Answer 6

Chapter 18, Problem 1TYK

Summary Introduction

Introduction:

The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.

Expert Solution & Answer

Answer to Problem 1TYK

Correct answer:

The sequence of nucleotides.

Explanation of Solution

Justification/ Explanation for the correct answer:

Option (a) is the sequence of nucleotides. The restriction enzymes help in recognition of restriction sites on the DNA fragments and cut them into different fragments. These restriction sites contain sequences of nucleotides that are recognized by enzymes and are palindromic in nature. There is a number of restriction enzymes identified for cutting DNA at specific restriction sites. Hence, option (a) is correct.

The explanation for the incorrect answers:

Option (b) is the length of DNA molecule. The activity of restriction enzymes depends on the presence of restriction sites on the DNA molecule. A long DNA molecule cannot be cut by an enzyme, if it does not contain particular recognition sites. So, it is an incorrect option.

Option (c) is whether it is closer to 5’end or 3´end of DNA molecule. The restriction enzymes recognize the palindromic sequence of DNA sequences, which can be read in both sides, from 5’ to 3´ and 3´ to 5´ ends. So, it is an incorrect option.

Option (d) is the number of copies of DNA molecule in a bacterial cell. A large number of copies of DNA cannot be cleaved by restriction enzymes without any restriction sites. So, it is an incorrect option.

Option (e) is the location of a start codon in a gene. Start codon only helps in the initiation of translation and protein synthesis. So, it is an incorrect option.

Hence, options (b), (c), (d) and (e) are incorrect.

Conclusion

Restriction sites are the sequence of DNA fragments which may vary in number and are recognized by a specific restriction endonuclease. The enzyme endonuclease cleaves the DNA fragment generating small fragments with sticky ends or blunt ends.

Answer 7

Chapter 18, Problem 1TYK

Summary Introduction

Introduction:

The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.

Answer 8

Expert Solution & Answer

Answer to Problem 1TYK

Correct answer:

The sequence of nucleotides.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Justification/ Explanation for the correct answer:

Option (a) is the sequence of nucleotides. The restriction enzymes help in recognition of restriction sites on the DNA fragments and cut them into different fragments. These restriction sites contain sequences of nucleotides that are recognized by enzymes and are palindromic in nature. There is a number of restriction enzymes identified for cutting DNA at specific restriction sites. Hence, option (a) is correct.

The explanation for the incorrect answers:

Option (b) is the length of DNA molecule. The activity of restriction enzymes depends on the presence of restriction sites on the DNA molecule. A long DNA molecule cannot be cut by an enzyme, if it does not contain particular recognition sites. So, it is an incorrect option.

Option (c) is whether it is closer to 5’end or 3´end of DNA molecule. The restriction enzymes recognize the palindromic sequence of DNA sequences, which can be read in both sides, from 5’ to 3´ and 3´ to 5´ ends. So, it is an incorrect option.

Option (d) is the number of copies of DNA molecule in a bacterial cell. A large number of copies of DNA cannot be cleaved by restriction enzymes without any restriction sites. So, it is an incorrect option.

Option (e) is the location of a start codon in a gene. Start codon only helps in the initiation of translation and protein synthesis. So, it is an incorrect option.

Hence, options (b), (c), (d) and (e) are incorrect.

Answer 12

Conclusion

Restriction sites are the sequence of DNA fragments which may vary in number and are recognized by a specific restriction endonuclease. The enzyme endonuclease cleaves the DNA fragment generating small fragments with sticky ends or blunt ends.

Answer 13

Ch. 18.1 - What features do restriction enzymes have in...Ch. 18.1 - Prob. 2SB Ch. 18.1 - What information and materials are needed to...Ch. 18.2 - What is a transgenic organism?Ch. 18.2 - Prob. 2SB Ch. 18.3 - What is a restriction fragment length polymorphism...Ch. 18.3 - Prob. 2SB Ch. 18.3 - Prob. 3SB Ch. 18 - Prob. 1TYK Ch. 18 - Prob. 2TYK

The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.

Concept explainers

Videos

Introduction:

The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.

Answer to Problem 1TYK

Explanation of Solution

Want to see more full solutions like this?

Chapter 18 Solutions

The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.

Concept explainers

Videos

Introduction: The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.

Answer to Problem 1TYK

Explanation of Solution

Want to see more full solutions like this?

Chapter 18 Solutions

Introduction:

The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.