Biology: The Dynamic Science (MindTap Course List)
Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN: 9781305389892
Author: Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher: Cengage Learning
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Chapter 18, Problem 1TYK
Summary Introduction

Introduction:

The joining of two or more DNA molecules from different sources generates a recombinant DNA. The joining of two DNA (deoxyribonucleic acid) molecules is the main part of gene cloning. The DNA molecules are cut by the restriction enzymes, also called restriction endonucleases.

Expert Solution & Answer
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Answer to Problem 1TYK

Correct answer:

The sequence of nucleotides.

Explanation of Solution

Justification/ Explanation for the correct answer:

Option (a) is the sequence of nucleotides. The restriction enzymes help in recognition of restriction sites on the DNA fragments and cut them into different fragments. These restriction sites contain sequences of nucleotides that are recognized by enzymes and are palindromic in nature. There is a number of restriction enzymes identified for cutting DNA at specific restriction sites. Hence, option (a) is correct.

The explanation for the incorrect answers:

Option (b) is the length of DNA molecule. The activity of restriction enzymes depends on the presence of restriction sites on the DNA molecule. A long DNA molecule cannot be cut by an enzyme, if it does not contain particular recognition sites. So, it is an incorrect option.

Option (c) is whether it is closer to 5’end or 3´end of DNA molecule. The restriction enzymes recognize the palindromic sequence of DNA sequences, which can be read in both sides, from 5’ to 3´ and 3´ to 5´ ends. So, it is an incorrect option.

Option (d) is the number of copies of DNA molecule in a bacterial cell. A large number of copies of DNA cannot be cleaved by restriction enzymes without any restriction sites. So, it is an incorrect option.

Option (e) is the location of a start codon in a gene. Start codon only helps in the initiation of translation and protein synthesis. So, it is an incorrect option.

Hence, options (b), (c), (d) and (e) are incorrect.

Conclusion

Restriction sites are the sequence of DNA fragments which may vary in number and are recognized by a specific restriction endonuclease. The enzyme endonuclease cleaves the DNA fragment generating small fragments with sticky ends or blunt ends.

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Students have asked these similar questions
Certain restriction endonucleases produce cohesive (sticky) ends.  This means that they: a. stick tightly to the ends of the DNA they have cut. b. cut both DNA strands at the same base pair. c.   make a staggered double-strand cut, leaving ends with a few nucleotides of single-stranded DNA protruding.   d. cut in regions of high GC content, leaving ends that can form more hydrogen bonds than ends of high AT content. e. cut in regions of high AT content, leaving ends that can form more hydrogen bonds than ends of high GC content.
Which of the following is a function of a restriction endonuclease?   a. It cleaves a DNA molecule at a specific site.   b. It cleaves a DNA molecule at random locations.   c. It removes specific codons from an mRNA molecule.   d. It removes specific exons from an mRNA molecule.
All of the following statements about telomerase are correct except: A. the RNA component acts as a template for the synthesis of a segment of DNA. B. it adds telomeric repeats to the 5'-ends of the DNA strands. C. it provides a mechanism for replicating the ends of linear chromosomes. D. it recognizes a G-rich single strand of DNA E. it is a reverse transcripcase.
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