(a) Interpretation: The products of the reaction between HCN and HO − are to be drawn. Concept introduction: The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H 2 O .

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Answer 1

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Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

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PLEASE READ!!! I DONT WANT EXAMPLES, I DONT WANT WORDS OR PARAGRAPHS FOR THE MECHANISM!!! THANKS First image: QUESTION 6. I have to show, with ARROWS and STRUCTURES, the mechanism of the reaction at the bottom. Also I have to show by mecanism why the reaction wouldn't work if the alcohol was primary. I also tried to draw the mechanism, tell me what to change. Please note that its an AMIDE thats formed not an AMINE the nitrogen has ONE hydrogen and one Phenyl-C-Phenyl. I already asked for this mechanism and got as a final product ...-NH2 not whats shown on the picture, thank you Ths second part. QUESTION 3. I just need a way to synthesize the lactone A, I already started please continue from where I left it Second image: I simply need the products, substrates or reagents, thank you

Indicate how to prepare a 10% sodium hydroxide (NaOH) solution to a slightly alkaline pH.

Answer 2

Question

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

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Answer 3

Question

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

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See solution

Answer 4

Question

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

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Answer 5

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

Answer 6

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Answer 7

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

Answer 9

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

Answer 10

Expert Solution & Answer

Answer 11

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Answer 12

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Answer 13

Ch. 18 - Prob. 18.1P Ch. 18 - Prob. 18.2P Ch. 18 - Prob. 18.3P Ch. 18 - Prob. 18.4P Ch. 18 - Prob. 18.5P Ch. 18 - Prob. 18.6P Ch. 18 - Prob. 18.7P Ch. 18 - Prob. 18.8P Ch. 18 - Prob. 18.9P Ch. 18 - Prob. 18.10P

(a) Interpretation: The products of the reaction between HCN and HO − are to be drawn. Concept introduction: The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H 2 O .

Solution Summary: The author explains that the products of the reaction between HCN and HO- are to be drawn.

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

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Chapter 18 Solutions

(a) Interpretation: The products of the reaction between HCN and HO − are to be drawn. Concept introduction: The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H 2 O .

Solution Summary: The author explains that the products of the reaction between HCN and HO- are to be drawn.

(a) Interpretation: The products of the reaction between HCN and HO− are to be drawn. Concept introduction: The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Want to see the full answer?

Chapter 18 Solutions

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.