The major product of the given reaction is to be predicted. Concept introduction: Intramolecular reactions are the ones in which the electron-rich and electron-poor sites are present within the same molecule. When ketones or aldehydes are treated with a strong base, they yield β -hydroxycarbonyl compounds via an aldol addition. Under these basic conditions, an enolate anion acts as a nucleophile. An intramolecular reaction is favored when it forms a five or six-membered ring. Intramolecular reactions involving the attack of an aldehyde C=O are favored over ones involving the attack of a ketone C=O . The first step is the formation of an enolate ion. The HO − reversibly deprotonates the alpha carbon to yield an enolate anion. In step two, the newly formed enolate anion, which serves as a nucleophile, attacks the carbonyl carbon present within the same molecule. The product of this step is an alkoxide ion, which is subsequently protonated in step 3.

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Answer 1

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18, Problem 18.33P

Interpretation Introduction

Interpretation:

The major product of the given reaction is to be predicted.

Concept introduction:

Intramolecular reactions are the ones in which the electron-rich and electron-poor sites are present within the same molecule. When ketones or aldehydes are treated with a strong base, they yield β-hydroxycarbonyl compounds via an aldol addition. Under these basic conditions, an enolate anion acts as a nucleophile. An intramolecular reaction is favored when it forms a five or six-membered ring. Intramolecular reactions involving the attack of an aldehyde C=O are favored over ones involving the attack of a ketone C=O. The first step is the formation of an enolate ion. The HO− reversibly deprotonates the alpha carbon to yield an enolate anion. In step two, the newly formed enolate anion, which serves as a nucleophile, attacks the carbonyl carbon present within the same molecule. The product of this step is an alkoxide ion, which is subsequently protonated in step 3.

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PLEASE READ!!! I DONT WANT EXAMPLES, I DONT WANT WORDS OR PARAGRAPHS FOR THE MECHANISM!!! THANKS First image: QUESTION 6. I have to show, with ARROWS and STRUCTURES, the mechanism of the reaction at the bottom. Also I have to show by mecanism why the reaction wouldn't work if the alcohol was primary. I also tried to draw the mechanism, tell me what to change. Please note that its an AMIDE thats formed not an AMINE the nitrogen has ONE hydrogen and one Phenyl-C-Phenyl. I already asked for this mechanism and got as a final product ...-NH2 not whats shown on the picture, thank you Ths second part. QUESTION 3. I just need a way to synthesize the lactone A, I already started please continue from where I left it Second image: I simply need the products, substrates or reagents, thank you

Answer 2

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18, Problem 18.33P

Interpretation Introduction

Interpretation:

The major product of the given reaction is to be predicted.

Concept introduction:

Intramolecular reactions are the ones in which the electron-rich and electron-poor sites are present within the same molecule. When ketones or aldehydes are treated with a strong base, they yield β-hydroxycarbonyl compounds via an aldol addition. Under these basic conditions, an enolate anion acts as a nucleophile. An intramolecular reaction is favored when it forms a five or six-membered ring. Intramolecular reactions involving the attack of an aldehyde C=O are favored over ones involving the attack of a ketone C=O. The first step is the formation of an enolate ion. The HO− reversibly deprotonates the alpha carbon to yield an enolate anion. In step two, the newly formed enolate anion, which serves as a nucleophile, attacks the carbonyl carbon present within the same molecule. The product of this step is an alkoxide ion, which is subsequently protonated in step 3.

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Answer 3

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18, Problem 18.33P

Interpretation Introduction

Interpretation:

The major product of the given reaction is to be predicted.

Concept introduction:

Intramolecular reactions are the ones in which the electron-rich and electron-poor sites are present within the same molecule. When ketones or aldehydes are treated with a strong base, they yield β-hydroxycarbonyl compounds via an aldol addition. Under these basic conditions, an enolate anion acts as a nucleophile. An intramolecular reaction is favored when it forms a five or six-membered ring. Intramolecular reactions involving the attack of an aldehyde C=O are favored over ones involving the attack of a ketone C=O. The first step is the formation of an enolate ion. The HO− reversibly deprotonates the alpha carbon to yield an enolate anion. In step two, the newly formed enolate anion, which serves as a nucleophile, attacks the carbonyl carbon present within the same molecule. The product of this step is an alkoxide ion, which is subsequently protonated in step 3.

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Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18, Problem 18.33P

Interpretation Introduction