Explanation Given information: ω is angular velocity of slab I A is moment of inertia of slab. A is the mass centre of the slab A is the instantaneous centre of rotation The velocity of A is pointed towards mass centre G. Concept used: Impulse-momentum principle Parallel axis theorem. Calculation: As per impulse momentum principle As per kinematics, ω = ω k r G / A = r G / A → θ therefore v G / A = ω r G / A = ω r G / A → β Where, β = θ + 90 0 Also, v ¯ = v A + v G / A We know that, h = r G / A × v G / A = ( r G / A ) ( v G / A ) k = ( r G / A ) ( ω × r G / A ) k = ( r G / A ) 2 ω k h = ( r G / A ) 2 ω taking moment about A, H A = r G / A × m v ¯ + I ω = �

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ISBN: 9781260265521

Author: BEER

Publisher: MCG

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Chapter 17.2, Problem 17.67P

To determine

HA= IAω when any one of the given conditions is satisfied.

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Chapter 17.2, Problem 17.66P

Chapter 17.2, Problem 17.68P

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