Explanation Given information: Gear A and B are connected to gear C as shown in the figure refer to the figure for details. Mass of gear A, m A = 675 g m = 0.675 k g Mass of gear B, m B = 675 g m = 0.675 k g The radius of gyration of gear A and B, k A = k B = 40 m m = 0.04 m Mass of gear C, m C = 3.6 k g The radius of gyration of gear C, k C = 100 m m = 0.1 m Couples for gear A, M A = 0.15 N . m Couples for gear B, M B = 0.15 N . m Couples for gear C, M C = 0.3 N . m Angular velocity of gear C, ω C = 2000 r p m = 66.67 π r a d / sec . Concept used: Impulse momentum principle, Calculation: From the figure, r A = 60 m m = 0.06 m r B = 60 m m = 0.06 m r C = 150 m m = 0.15 m Weight of gear A, w A = m A × g = 6.622 N Weight of gear B, w B = m B × g = 6.622 N Weight of gear C, w C = m C × g = 35.316 N From kinematics, v A = v B = v C r A ω A = r B ω B = r C ω C ω A = ω B = 0.15 × 66.67 π 0.06 = 523.62 r a d / sec Applying the impulse-momentum principle for each gear. (a)for gear A, Taking moment about A, ( w A ) f = 0 I A ω A + r A ∫ F A C d t − ( M A ) f t = 0 ---------------------(1) (b)for gear B, Taking a moment of about B, ( w B ) f = 0 I B ω B + r B ∫ F B C d t − ( M B ) f t = 0 ----------------------(2) (c)for gear C,

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ISBN: 9781260265521

Author: BEER

Publisher: MCG

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Chapter 17.2, Problem 17.61P

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The time required for the system to come to rest.

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Chapter 17.2, Problem 17.60P

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The time required for the system to come to rest.

Solution Summary: The author explains the time required for the system to come to rest. Gear A and B are connected to gear C.

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