Explanation Given information: Mass of the disk (m) = 4kg. Radius of the disk (r) = 75mm. Velocity of the belt (v) = 18m/s. Coefficient of friction between disk and belt ( μ k ) = 0.25 Calculation: Let the initial kinetic energy of disk is E 1 , final kinetic energy of disk is E 2 and work done by the disk is W. Work done on the machine is negative and work done by the machine is positive. So, equation of principle of work and energy is: E 1 +W = E 2 .... (1) Initially disk is at rest therefore initial value of kinetic energy is zero. So E 1 =0 Final value of kinetic energy E 2 = 1 2 I ω 2 2 Where, ω 2 = v r ω 2 = 18 0.075 ω 2 = 240 r a d i a n / s And I = 1 2 m r 2 I = 1 2 × 4 × 0.075 2 I = 0.01125 k g − m 2 Now substitute the value of I and ω 2 E 2 = 1 2 I ω 2 2 E 2 = 1 2 × 0

12th Edition

ISBN: 9781260265521

Author: BEER

Publisher: MCG

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Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be create…

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Chapter 17.1, Problem 17.7P

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Number of revolutions by the disk.

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Number of revolutions by the disk.

Solution Summary: The author explains the equation of principle of work and energy: E 1 + W = E 2. The initial value of kinetic energy is zero.

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Number of revolutions by the disk.

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