Explanation Given information: Radius of drum (r) = 10 in. Mass moment of inertia (I) = 16 lb-ft-s 2 . Coefficient of kinetic friction between drum and brake shoe ( μ k ) = 0.40. Initial angular velocity (N) = 240rpm anti clockwise. Total number of revolutions by the system ( θ ) = 75 rev Calculation: Initial kinetic energy E 1 = 1 2 I ω 2 E 1 = 1 2 × 16 × ( 2 π N 60 ) 2 E 1 = 8 × ( 2 π × 240 60 ) 2 E 1 = 8 × ( 8 π ) 2 E 1 = 5048.12 l b − f t Final kinetic energy is zero because gear is to be stop at last E 2 =0 Moment about centre of the drum C = f r C = f × 10 i n C = f × ( 10 × 1 12 f t ) C = 0.833 f Work done W = C × θ W = 0.833 f × 75 r e v W = 0.833 f × ( 75 × 2 π r a d ) W = 392

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ISBN: 9781260265521

Author: BEER

Publisher: MCG

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Force exerted by the hydraulic cylinder.

Solution Summary: The author explains the force exerted by the hydraulic cylinder is, F=109.39 lb.

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