Q2: Draw the shear and bending-moment diagrams for the beam and loading shown, and determine the maximum absolute value of (a) the shear, (b) the bending moment. (C) Deflection @A, (d), Slope @A, use beams' formula tables and/or direct integration method if necessary 60 lbs Weight of the beam= Uniformly distributed load= 5lb/in M=25 lb-in C D E B A 9 in. 12 in. 9 in. 12 in. Shear Force = b) -60+6(42)-150lbs. bending moment BM = = -25-60x33+5 6411b-in 5₁ = 5 (42)" S 2 = 8E1 = (나를) 2 WL = 1944810 2EL El -22050 = 2E1 El 32670 1012770 = -25(422) c) deflection A S 5 3 - 71840 = 607332 2E. = 32670 E El 5=51 +52 +53 S = 1944810 Slope A d)6(42) 6E1 61740 E 1050 El 22050 1012770 = Ez E3 90990 El 61740 -25142 = = El 32670 980 El E E E -1056 E1

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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from this problem a want you to help to draw the shear moment and the bending moment 

Q2:
Draw the shear and bending-moment diagrams for the beam and loading shown, and determine the maximum absolute value
of (a) the shear, (b) the bending moment. (C) Deflection @A, (d), Slope @A, use beams' formula tables and/or direct integration method if necessary
60 lbs
Weight of the beam= Uniformly
distributed load= 5lb/in
M=25 lb-in
C
D
E
B
A
9 in.
12 in.
9 in.
12 in.
Shear Force =
b)
-60+6(42)-150lbs.
bending moment
BM
=
=
-25-60x33+5
6411b-in
5₁ = 5 (42)"
S
2
=
8E1
=
(나를)
2
WL =
1944810
2EL
El
-22050
=
2E1
El
32670
1012770
=
-25(422)
c) deflection A
S
5 3
-
71840
=
607332
2E.
= 32670
E
El
5=51 +52 +53
S = 1944810
Slope A
d)6(42)
6E1
61740
E
1050
El
22050
1012770
=
Ez
E3
90990
El
61740
-25142
=
=
El
32670
980
El
E
E
E
-1056
E1
Transcribed Image Text:Q2: Draw the shear and bending-moment diagrams for the beam and loading shown, and determine the maximum absolute value of (a) the shear, (b) the bending moment. (C) Deflection @A, (d), Slope @A, use beams' formula tables and/or direct integration method if necessary 60 lbs Weight of the beam= Uniformly distributed load= 5lb/in M=25 lb-in C D E B A 9 in. 12 in. 9 in. 12 in. Shear Force = b) -60+6(42)-150lbs. bending moment BM = = -25-60x33+5 6411b-in 5₁ = 5 (42)" S 2 = 8E1 = (나를) 2 WL = 1944810 2EL El -22050 = 2E1 El 32670 1012770 = -25(422) c) deflection A S 5 3 - 71840 = 607332 2E. = 32670 E El 5=51 +52 +53 S = 1944810 Slope A d)6(42) 6E1 61740 E 1050 El 22050 1012770 = Ez E3 90990 El 61740 -25142 = = El 32670 980 El E E E -1056 E1
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