Explanation Given information: Mass of the cylinder A (m) = 4kg. Radius of the cylinder A (r) = 150mm. Angular velocity of the cylinder A (w) = 50 rad/s. Coefficient of friction between cylinder A and B is μ k . Revolutions of cylinder A ( θ A ) = 3 rev. Revolutions of cylinder B ( θ B ) = 1rev. Calculation: Let us consider the initial kinetic energy of disk is E 1 , final kinetic energy of disk is E 2 and work done by the cylinder is W. Both the cylinders are identical so final angular velocity is same. For Cylinder A: Work done on the cylinder, so it is negative E 1 − W = E 2 E 1 − C θ A = E 2 ( 1 ) For cylinder B: Work done by the cylinder, so it is positive. Initial kinetic energy is zero because cylinder B is in rest. E 1 + W = E 2 0 + C θ B = E 2 E 2 = C θ B ( 2 ) Now from equation 1 E 1 − W = E 2 E 1 − C θ A = C θ B C θ A + C θ B = E 1 C ( θ A + θ B ) = 1 2 I ω o 2 C = I ω o 2 To determine (b) Coefficient of kinetic friction μ k .

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ISBN: 9781260265521

Author: BEER

Publisher: MCG

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Chapter 17.1, Problem 17.8P

To determine

(a)

Final angular velocity of cylinder A and B.

To determine

(b)

Coefficient of kinetic friction μk.

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Chapter 17.1, Problem 17.7P

Chapter 17.1, Problem 17.9P

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(a) Final angular velocity of cylinder A and B.

Solution Summary: The author calculates the final angular velocity of cylinders A and B.