Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
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Chapter 17, Problem 45P
Compound Y
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Treatment of 2-methylpropanenitrile [(CH3)2CHCN] with CH3CH2CH2MgBr, followed by aqueous acid, affords compound V, which has molecular formula C7H14O. V has a strong absorption in its IR spectrum at 1713 cm−1, and gives the following 1H NMR data: 0.91 (triplet, 3 H), 1.09 (doublet, 6 H), 1.6 (multiplet, 2 H), 2.43 (triplet, 2 H), and 2.60 (septet, 1 H) ppm. What is the structure of V? We will learn about this reaction in Chapter 20.
A hydrocarbon, compound B, has molecular formula C6H6, and gave an NMR spectrum with two signals: delta 6.55 pm and delta 3.84 pm with peak ratio of 2:1. When warmed in pyridine for three hr, compound B quantitatively converts to benzene. Mild hydrogenation of B yielded another compound C with mass spectrum of m/z 82. Infrared spectrum showed no double bonds; NMR spectrum showed one broad peak at delta 2.34 ppm. With this information, address the following questions.
a) How many rings are in compound C?
b) How many rings are probably in B? How many double bonds are in B?
c) Can you suggest a structure for compounds B and C?
d) In the NMR spectrum of B, the up-field signal was a quintet, and the down field signal was a triplet. How must you account for these splitting patterns?
An unknown compound C3H2NCl shows moderately strong IR absorptions around 1650 cm-1 and 2200 cm-1. Its NMR spectrum consists of two doublets (J = 14 Hz) at δ 5.9 and δ 7.1. Propose a structure consistent with this data?
Chapter 17 Solutions
Organic Chemistry
Ch. 17 - Practice Problem 17.1 Give an IUPAC systematic...Ch. 17 - Prob. 2PPCh. 17 - Practice Problem 17.3 Write structural formulas...Ch. 17 - Practice Problem 17.4
Show how each of the...Ch. 17 - Practice Problem 17.5
Show how you could prepare...Ch. 17 - Practice Problem 17.6
(a) Which of the carboxylic...Ch. 17 - Prob. 7PPCh. 17 - Prob. 8PPCh. 17 - Practice Problem 17.9
Esters can also be...Ch. 17 - Prob. 10PP
Ch. 17 - Prob. 11PPCh. 17 - Practice Problem 17.12
What products would you...Ch. 17 - Practice Problem 17.13 (a) Provide the reagents...Ch. 17 - Prob. 14PPCh. 17 - Practice Problem 17.15 Using decarboxylation...Ch. 17 - Practice Problem 17.16 Diacyl peroxides, ,...Ch. 17 - Prob. 17PCh. 17 - Give an IUPAC systematic or common name for each...Ch. 17 - Prob. 19PCh. 17 - Prob. 20PCh. 17 - 17.21 What major organic product would you expect...Ch. 17 - Prob. 22PCh. 17 - Prob. 23PCh. 17 - Prob. 24PCh. 17 - Prob. 25PCh. 17 - 17.26 What products would you expect to obtain...Ch. 17 - Write structural formulas for the major organic...Ch. 17 - 17.28 Indicate reagents that would accomplish each...Ch. 17 - Write structural formulas for the major organic...Ch. 17 - Prob. 30PCh. 17 - Prob. 31PCh. 17 - Prob. 32PCh. 17 - 17.33 On heating,...Ch. 17 - Prob. 34PCh. 17 - Prob. 35PCh. 17 - 17.36 Show how pentanoic acid can be prepared from...Ch. 17 - 17.37 The active ingredient of the insect...Ch. 17 - Prob. 38PCh. 17 - Prob. 39PCh. 17 - Give stereochemical formulas for compounds AQ:...Ch. 17 - 17.41 -Glyceraldehyde can be transformed into...Ch. 17 - Prob. 42PCh. 17 - Prob. 43PCh. 17 - 17.44 Given here are the NMR spectra and carbonyl...Ch. 17 - 17.45 Compound Y dissolves slowly when warmed...Ch. 17 - Prob. 46PCh. 17 - Prob. 47PCh. 17 - Prob. 48PCh. 17 - Prob. 49PCh. 17 - Prob. 50PCh. 17 - Prob. 51PCh. 17 - 17.52 Starting with 1-naphthol, suggest an...Ch. 17 - Suggest a synthesis of ibuprofen (Section 5.11)...Ch. 17 - Prob. 54PCh. 17 - Prob. 55PCh. 17 - Prob. 1LGPCh. 17 - Prob. 2LGPCh. 17 - Prob. 3LGPCh. 17 - Prob. 4LGP
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- Ketones undergo a reduction when treated with sodium borohydride, NaBH4. What is the structure of the compound produced by reaction of 2-butanone with NaBH4 if it has an IR absorption at 3400 cm-1 and M+=74 in the mass spectrum?arrow_forwardAddition of m-xylene to the strongly acidic solvent HF/SbF5 at 45C gives a new species, which shows 1H-NMR resonances at 2.88 (3H), 3.00 (3H), 4.67 (2H), 7.93 (1H), 7.83 (1H), and 8.68 (1H). Assign a structure to the species giving this spectrum.arrow_forwardReaction of (CH3)3CCHO with (C6H5)3P=C(CH3)OCH3, followed bytreatment with aqueous acid, affords R (C7H14O). R has a strong absorption in its IR spectrum at 1717 cm−1 and three singlets in its 1H NMR spectrum at 1.02 (9 H), 2.13 (3 H), and 2.33 (2 H) ppm. What is thestructure of R?arrow_forward
- Treatment of compound D with LiAlH4 followed by H2O forms compound E. D shows a molecular ion in its mass spectrum at m/z = 71 and IR absorptions at 3600–3200 and 2263 cm–1. E shows a molecular ion in its mass spectrum at m/z = 75 and IR absorptions at 3636 and 3600–3200 cm–1. Propose structures for D and E from these data and the given 1H NMR spectra.arrow_forwardCompounds A and B are isomers having the molecular formula C4H8O3. Identify A and B on the basis of their 1H NMR spectra.Compound A: δ 1.3 (3H, triplet); 3.6 (2H, quartet); 4.1 (2H, singlet); 11.1 (1H, broad singlet)Compound B: δ 2.6 (2H, triplet); 3.4 (3H, singlet); 3.7 (2H triplet); 11.3 (1H, broad singlet)arrow_forwardReaction of (CH3)3CCHO with (C6H5)3P=C(CH3)OCH3, followed by treatment with aqueous acid, affords R (C7H14O). R has a strong absorption in its IR spectrum at 1717 cm−1 and three singlets in its 1H NMR spectrum at 1.02 (9 H), 2.13 (3 H), and 2.33 (2 H) ppm. What is the structure of R? We will learn about this reaction in Chapter 18.arrow_forward
- Propose a structure for a compound of molecular formula C3H8O with an IR absorption at 3600–3200 cm−1 and the following NMR spectrum:arrow_forwardThe 1H-NMR spectrum of compound R, C6H14O, consists of two signals: d 1.1 (doublet) and d 3.6 (septet) in the ratio 6:1. Propose a structural formula for compound R consistent with this informationarrow_forwardProvide a structure for the compound with molecular formula C5H10O and with the following spectroscopic data.IR: 1720 cm−11H NMR: 0.9δ (triplet, I=3H), 1.7δ (sextet, I=2H), 2.1δ (singlet, I=3H), 2.4δ (triplet, I=2H)arrow_forward
- Treatment of the bicyclic chloride A with lithium in tetrahydrofuran (THF) gave the monocyclic product B, C,H,Li. In deuterated THF, B exhibited a single proton NMR signal at 6.72 ppm and a single 13 C-NMR signal at about 110 ppm. Treatment of B with tetraethylammonium chloride gave a white solid in which N(C2H5)4 replaces Li. Draw a structure for the lithium derivative B. A Li/THF -CI CgHgLi (C2H5)4N CI C9H9N(C2H5)4 B Draw cations and anions in separate sketchers. ⚫ Separate structures with + signs from the drop-down menu.arrow_forwardAs reaction of (CH3)2CO with LIC≡CH followed by H2O affords compound D, which has a molecular ion in its mass spectrum at 84 and prominent absorptions in its IR spectrum at 3600−3200, 3303, 2938, and 2120 cm−1. D shows the following 1H NMR spectral data: 1.53 (singlet, 6 H), 2.37 (singlet, 1 H), and 2.43 (singlet, 1 H) ppm. What is the structure of D?arrow_forwardA molecule of the molecular formula C5H11Br gives rise to the NMR spectrum below. When reacted with NaOH and water, it forms a product which by NMR has 2 protons 1H at 5.4 ppm and 1H at 5.5 ppm each having a 3J coupling of 17 Hz. (other protons also present) The product also has an IR stretch at 1550 cm 1. Provide the structures of the starting material and product. NaOH H,0 C;H„Br 6H triplet 4H quintet 1H quintet 10 8 Ppmarrow_forward
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