Interpretation:
This is to be explained how having large amount of reactants does not ensure the high yield of products.
Concept introduction:
If a reaction has an equilibrium constant greater than 1 the reaction is not very feasible.

Answer to Problem 42A
An equilibrium system can contain small and unchanging products even on having large amount of reactants of the reaction is reversible and not much yielding. The equilibrium constant for such a reaction will be much larger than 1.
Explanation of Solution
The equilibrium constant of a reaction depends on the concentration of products and reactants. If the concentration of product is much higher than the concentration of reactant at equilibrium, the value of keqbecome larger than 1.
The relative size of Keqfor a reaction with a low yield becomes very much larger than 1.
Chapter 17 Solutions
Chemistry: Matter and Change
Additional Science Textbook Solutions
Concepts of Genetics (12th Edition)
Microbiology: An Introduction
College Physics: A Strategic Approach (3rd Edition)
Campbell Biology (11th Edition)
Biology: Life on Earth (11th Edition)
Introductory Chemistry (6th Edition)
- Indicate the order of basicity of primary, secondary and tertiary amines.arrow_forward> Classify each of the following molecules as aromatic, antiaromatic, or nonaromatic. Cl Z- N O aromatic O antiaromatic O nonaromatic O aromatic O antiaromatic O nonaromatic O aromatic ○ antiaromatic nonaromaticarrow_forwardPlease help me answer this question. I don't understand how or even if this can happen in a single transformation. Please provide a detailed explanation and a drawing showing how it can happen in a single transformation. Add the necessary reagents and reaction conditions above and below the arrow in this organic reaction. If the products can't be made from the reactant with a single transformation, check the box under the drawing area instead.arrow_forward
- 2) Draw the correct chemical structure (using line-angle drawings / "line structures") from their given IUPAC name: a. (E)-1-chloro-3,4,5-trimethylhex-2-ene b. (Z)-4,5,7-trimethyloct-4-en-2-ol C. (2E,6Z)-4-methylocta-2,6-dienearrow_forwardපිපිම Draw curved arrows to represent the flow of electrons in the reaction on the left Label the reactants on the left as either "Acid" or "Base" (iii) Decide which direction the equilibrium arrows will point in each reaction, based on the given pk, values (a) + H-O H 3-H + (c) H" H + H****H 000 44-00 NH₂ (e) i Дон OH Ө NHarrow_forward3) Label the configuration in each of the following alkenes as E, Z, or N/A (for non-stereogenic centers). 00 E 000 N/A E Br N/A N/A (g) E N/A OH E (b) Oz N/A Br (d) 00 E Z N/A E (f) Oz N/A E (h) Z N/Aarrow_forward
- 6) Fill in the missing Acid, pKa value, or conjugate base in the table below: Acid HCI Approximate pK, -7 Conjugate Base H-C: Hydronium (H₂O') -1.75 H-O-H Carboxylic Acids (RCOOH) Ammonium (NH4) 9.24 Water (H₂O) H-O-H Alcohols (ROH) RO-H Alkynes R--H Amines 25 25 38 HOarrow_forward5) Rank the following sets of compounds in order of decreasing acidity (most acidic to least acidic), and choose the justification(s) for each ranking. (a) OH V SH я вон CH most acidic (lowst pKa) least acidic (highest pKa) Effect(s) Effect(s) Effect(s) inductive effect O inductive effect O inductive effect electronegativity electronegativity O electronegativity resonance polarizability resonance polarizability O resonance O polarizability hybridization Ohybridization O hybridization оarrow_forwardHow negatively charged organic bases are formed.arrow_forward
- Nonearrow_forward1) For the following molecules: (i) Label the indicated alkenes as either cis (Z), trans (E), or N/A (for non-stereogenic centers) by bubbling in the appropriate label on the molecule. (ii) Complete the IUPAC name located below the structure (HINT: Put the letter of the configuration in parentheses at the beginning of the name!) E z N/A ()-3,4,6-trimethylhept-2-ene E Oz O N/A ()-3-ethyl-1-fluoro-4-methylhex-3-ene E -+- N/A Me )-2,3-dimethylpent-2-ene (d) (b) E O N/A Br ()-5-bromo-1-chloro-3-ethyloct-4-ene ОЕ Z N/A Et (___)-3-ethyl-4-methylhex-3-ene E (f) Oz N/A z N/A HO (4.7)-4-(2-hydroxyethyl)-7-methylnona-4,7-dien-2-onearrow_forwardO 9:21AM Tue Mar 4 ## 64% Problem 51 of 15 Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. H :0: CI. AI :CI: :CI: Cl AI Select to Add Arrows Select to Add Arrows O: Cl :CI: :0: H CI: CI CO Select to Add Arrows Select to Add Arrows :O: CI :0: Cl. 10: AIarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





