Chapter 17.1, Problem 2PP

Solution

Interpretation:

- The chemical equation for a constant equilibrium expression is to be written.

Concept introduction:

- The equilibrium constant expresses for a general chemical equation is $K_C=\frac{[R][S]}{[P][Q]}=\frac{\text{[Product]}}{\text{[Reactant]}}$

Then general chemical equation for this is

$\text{Reactants}\rightleftharpoons \text{Products}$

$\text{[P]+[Q]}\rightleftharpoons \text{[R]+[S]}$.

The general chemical equation is

$2C{O}_2\rightleftharpoons 2CO+O_2$.

The equilibrium constant is the ratio of the molar concentration of product and molar concentration of reactant with each concentration term raised to the power equal to the number of moles in the balanced chemical equation.

It is donated by $K_C$.

For e.g. $K_C=\frac{{[C]}^c}{{[A]}^a{[B]}^b}=\frac{\text{[Product]}}{\text{[Reactant]}}$

Chemical equation for this $\text{'}{K}_C\text{'}$ is

$aA+bB\rightleftharpoons c$.

This is also known as law of chemical equilibrium.

Chemical equation for

$K_C=\frac{{[CO]}^2[O_2]}{[C{O}_2]}$

$2C{O}_2\rightleftharpoons 2CO+O_2$.

The chemical equation is as follows

$2C{O}_2\rightleftharpoons 2CO+O_2$.