EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR
EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR
8th Edition
ISBN: 9780357022078
Author: Larson
Publisher: CENGAGE L
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Concept explainers

Correlation
Correlation defines a relationship between two independent variables. It tells the degree to which variables move in relation to each other. When two sets of data are related to each other, there is a correlation between them.
Linear Correlation
A correlation is used to determine the relationships between numerical and categorical variables. In other words, it is an indicator of how things are connected to one another. The correlation analysis is the study of how variables are related.
Regression Analysis
Regression analysis is a statistical method in which it estimates the relationship between a dependent variable and one or more independent variable. In simple terms dependent variable is called as outcome variable and independent variable is called as p…
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Question
Book Icon
Chapter 1.7, Problem 32E

(a)

To determine

To find: The equation and correlation coefficient value.

(a)

Expert Solution
Check Mark

Answer to Problem 32E

The correlation coefficient that represents the graph.

Explanation of Solution

Given information:

The least squares regression line for a set of data. The equations and r-values for the models are given.

  y = 0.68x + 2.7y = 0.41x + 2.7y = −0.62x + 10.0r = 0.973r = −0.986r = 0.624

Formula used:

The TI83 calculator is used.

Calculation:

Consider the following equation

  y=0.68x+2.7

Use TI83 calculator to draw the graph of the equation

Step1: Press Y: button and enter the above equation

The display is as shown below

  EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR, Chapter 1.7, Problem 32E , additional homework tip 1

Step2: Press WINDOW button and set the range of the axis

The display is as shown below

  EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR, Chapter 1.7, Problem 32E , additional homework tip 2

Step3: Press Graph button to graph the above sequence

The display is as shown below

  EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR, Chapter 1.7, Problem 32E , additional homework tip 3

Note that the above graph is same as the graph provide in option (iii).

Therefore, the equation y=0.68x+2.7 represents the graph (iii)

Also, since the slope of the equation y = 0.68x + 2.7 is most positive, therefore the correlation coefficient that reprints the graph (iii) is 0.973

Consider the following equation

  y=0.41x+2.7

Use TI83 calculator to draw the graph of the equation

Step1: Press Y: button and enter the above equation

The display is as shown below

  EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR, Chapter 1.7, Problem 32E , additional homework tip 4

Step2: Press WINDOW button and set the range of the axis

The display is as shown below

  EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR, Chapter 1.7, Problem 32E , additional homework tip 5

Step3: Press Graph button to graph the above sequence

The display is as shown below

  EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR, Chapter 1.7, Problem 32E , additional homework tip 6

Note that the above graph is same as the graph provide in option (ii).

Therefore, the equation y = 0.41x + 2.7 represents the graph (ii)

Also, since the slope of the equation y = 0.41x + 2.7 is second most positive, therefore the correlation coefficient that represents the graph (ii) is 0.624

Consider the following equation

  y=−0.62x+10.0

Use T|83 calculator to draw the graph of the equation

Step1: Press Y: button and enter the above equation

The display is as shown below

  EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR, Chapter 1.7, Problem 32E , additional homework tip 7

Step2: Press WINDOW button and set the range of the axis

The display is as shown below

  EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR, Chapter 1.7, Problem 32E , additional homework tip 8

Step3: Press Graph button to graph the above sequence

The display is as shown below

  EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR, Chapter 1.7, Problem 32E , additional homework tip 9

Note that the above graph is same as the graph provide in option (i).

Therefore, the equation y=−0.62x+10.0 represents the graph (i)

Also, since the slope of the equation y=−0.62x+10.0 is negative, therefore the correlation coefficient that represents the graph (i) is -0.986

Conclusion:

The correlation coefficient that represents the graph.

(b)

To determine

To analyse: The model that best fits the data.

(b)

Expert Solution
Check Mark

Answer to Problem 32E

The model number 3 fits the data well which represents y=−0.62x+10 equation because it has closest |r|≤1

Explanation of Solution

Given information:

According to the correlation coefficients, to determine the best fit for the data.

Formula used:

Correlation coefficients are used.

Calculation:

According to the correlation coefficients, model number 3 fits the data well which represents y=−0.62x+10 equation because it has closest |r|≤1

Conclusion:

The model number 3 fits the data well which represents y=−0.62x+10 equation because it has closest |r|≤1 .

Previous
Chapter 1.7, Problem 31E
Next
Chapter 1.7, Problem 33E

Chapter 1 Solutions

EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR

Ch. 1.1 - Prob. 1ECh. 1.1 - Prob. 2ECh. 1.1 - Prob. 3ECh. 1.1 - Prob. 4ECh. 1.1 - Prob. 5ECh. 1.1 - Prob. 6ECh. 1.1 - Prob. 7ECh. 1.1 - Prob. 8ECh. 1.1 - Prob. 9ECh. 1.1 - Prob. 10E
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Prob. 6ECh. 1.6 - Prob. 7ECh. 1.6 - Prob. 8ECh. 1.6 - Prob. 9ECh. 1.6 - Prob. 10ECh. 1.6 - Prob. 11ECh. 1.6 - Prob. 12ECh. 1.6 - Prob. 13ECh. 1.6 - Prob. 14ECh. 1.6 - Prob. 15ECh. 1.6 - Prob. 16ECh. 1.6 - Prob. 17ECh. 1.6 - Prob. 18ECh. 1.6 - Prob. 19ECh. 1.6 - Prob. 20ECh. 1.6 - Prob. 21ECh. 1.6 - Prob. 22ECh. 1.6 - Prob. 23ECh. 1.6 - Prob. 24ECh. 1.6 - Prob. 25ECh. 1.6 - Prob. 26ECh. 1.6 - Prob. 27ECh. 1.6 - Prob. 28ECh. 1.6 - Prob. 29ECh. 1.6 - Prob. 30ECh. 1.6 - Prob. 31ECh. 1.6 - Prob. 32ECh. 1.6 - Prob. 33ECh. 1.6 - Prob. 34ECh. 1.6 - Prob. 35ECh. 1.6 - Prob. 36ECh. 1.6 - Prob. 37ECh. 1.6 - Prob. 38ECh. 1.6 - Prob. 39ECh. 1.6 - Prob. 40ECh. 1.6 - Prob. 41ECh. 1.6 - Prob. 42ECh. 1.6 - Prob. 43ECh. 1.6 - Prob. 44ECh. 1.6 - Prob. 45ECh. 1.6 - Prob. 46ECh. 1.6 - Prob. 47ECh. 1.6 - Prob. 48ECh. 1.6 - Prob. 49ECh. 1.6 - Prob. 50ECh. 1.6 - Prob. 51ECh. 1.6 - Prob. 52ECh. 1.6 - Prob. 53ECh. 1.6 - Prob. 54ECh. 1.6 - Prob. 55ECh. 1.6 - Prob. 56ECh. 1.6 - Prob. 57ECh. 1.6 - Prob. 58ECh. 1.6 - Prob. 59ECh. 1.6 - Prob. 60ECh. 1.6 - Prob. 61ECh. 1.6 - Prob. 62ECh. 1.6 - Prob. 63ECh. 1.6 - Prob. 64ECh. 1.6 - Prob. 65ECh. 1.6 - Prob. 66ECh. 1.6 - Prob. 67ECh. 1.6 - Prob. 68ECh. 1.6 - Prob. 69ECh. 1.6 - Prob. 70ECh. 1.6 - Prob. 71ECh. 1.6 - Prob. 72ECh. 1.6 - Prob. 73ECh. 1.6 - Prob. 74ECh. 1.6 - Prob. 75ECh. 1.6 - Prob. 76ECh. 1.6 - Prob. 77ECh. 1.6 - Prob. 78ECh. 1.6 - Prob. 79ECh. 1.6 - Prob. 80ECh. 1.6 - Prob. 81ECh. 1.6 - Prob. 82ECh. 1.6 - Prob. 83ECh. 1.6 - Prob. 84ECh. 1.6 - Prob. 85ECh. 1.6 - Prob. 86ECh. 1.6 - Prob. 87ECh. 1.6 - Prob. 88ECh. 1.6 - Prob. 89ECh. 1.6 - Prob. 90ECh. 1.6 - Prob. 91ECh. 1.6 - Prob. 92ECh. 1.6 - Prob. 93ECh. 1.6 - Prob. 94ECh. 1.6 - Prob. 95ECh. 1.6 - Prob. 96ECh. 1.6 - Prob. 97ECh. 1.6 - Prob. 98ECh. 1.6 - Prob. 99ECh. 1.6 - Prob. 100ECh. 1.6 - Prob. 101ECh. 1.6 - Prob. 102ECh. 1.6 - Prob. 103ECh. 1.6 - Prob. 104ECh. 1.6 - Prob. 105ECh. 1.6 - Prob. 106ECh. 1.6 - Prob. 107ECh. 1.6 - Prob. 108ECh. 1.6 - Prob. 109ECh. 1.6 - Prob. 110ECh. 1.6 - Prob. 111ECh. 1.6 - Prob. 112ECh. 1.6 - Prob. 113ECh. 1.6 - Prob. 114ECh. 1.6 - Prob. 115ECh. 1.6 - Prob. 116ECh. 1.6 - Prob. 117ECh. 1.6 - Prob. 118ECh. 1.6 - Prob. 119ECh. 1.6 - Prob. 120ECh. 1.6 - Prob. 121ECh. 1.6 - Prob. 122ECh. 1.6 - Prob. 123ECh. 1.6 - Prob. 124ECh. 1.6 - Prob. 125ECh. 1.6 - Prob. 126ECh. 1.6 - Prob. 127ECh. 1.6 - Prob. 128ECh. 1.6 - Prob. 129ECh. 1.6 - Prob. 130ECh. 1.6 - Prob. 131ECh. 1.6 - Prob. 132ECh. 1.6 - Prob. 133ECh. 1.6 - Prob. 134ECh. 1.6 - Prob. 135ECh. 1.6 - Prob. 136ECh. 1.6 - Prob. 137ECh. 1.6 - Prob. 138ECh. 1.6 - Prob. 139ECh. 1.6 - Prob. 140ECh. 1.6 - Prob. 141ECh. 1.6 - Prob. 142ECh. 1.6 - Prob. 143ECh. 1.6 - Prob. 144ECh. 1.7 - Prob. 1ECh. 1.7 - Prob. 2ECh. 1.7 - Prob. 3ECh. 1.7 - Prob. 4ECh. 1.7 - Prob. 5ECh. 1.7 - Prob. 6ECh. 1.7 - Prob. 7ECh. 1.7 - Prob. 8ECh. 1.7 - Prob. 9ECh. 1.7 - Prob. 10ECh. 1.7 - Prob. 11ECh. 1.7 - Prob. 12ECh. 1.7 - Prob. 13ECh. 1.7 - Prob. 14ECh. 1.7 - Prob. 15ECh. 1.7 - Prob. 16ECh. 1.7 - Prob. 17ECh. 1.7 - Prob. 18ECh. 1.7 - Prob. 19ECh. 1.7 - Prob. 20ECh. 1.7 - Prob. 21ECh. 1.7 - Prob. 22ECh. 1.7 - Prob. 23ECh. 1.7 - Prob. 24ECh. 1.7 - Prob. 25ECh. 1.7 - Prob. 26ECh. 1.7 - Prob. 27ECh. 1.7 - Prob. 28ECh. 1.7 - Prob. 29ECh. 1.7 - Prob. 30ECh. 1.7 - Prob. 31ECh. 1.7 - Prob. 32ECh. 1.7 - Prob. 33ECh. 1.7 - Prob. 34ECh. 1 - Prob. 1CRCh. 1 - Prob. 2CRCh. 1 - Prob. 3CRCh. 1 - Prob. 4CRCh. 1 - Prob. 5CRCh. 1 - Prob. 6CRCh. 1 - Prob. 7CRCh. 1 - Prob. 8CRCh. 1 - Prob. 9CRCh. 1 - Prob. 10CRCh. 1 - Prob. 11CRCh. 1 - Prob. 12CRCh. 1 - Prob. 13CRCh. 1 - Prob. 14CRCh. 1 - Prob. 15CRCh. 1 - Prob. 16CRCh. 1 - Prob. 17CRCh. 1 - Prob. 18CRCh. 1 - Prob. 19CRCh. 1 - Prob. 20CRCh. 1 - Prob. 21CRCh. 1 - Prob. 22CRCh. 1 - Prob. 23CRCh. 1 - Prob. 24CRCh. 1 - Prob. 25CRCh. 1 - Prob. 26CRCh. 1 - Prob. 27CRCh. 1 - Prob. 28CRCh. 1 - Prob. 29CRCh. 1 - Prob. 30CRCh. 1 - Prob. 31CRCh. 1 - Prob. 32CRCh. 1 - Prob. 33CRCh. 1 - Prob. 34CRCh. 1 - Prob. 35CRCh. 1 - Prob. 36CRCh. 1 - Prob. 37CRCh. 1 - Prob. 38CRCh. 1 - Prob. 39CRCh. 1 - Prob. 40CRCh. 1 - Prob. 41CRCh. 1 - Prob. 42CRCh. 1 - Prob. 43CRCh. 1 - Prob. 44CRCh. 1 - Prob. 45CRCh. 1 - Prob. 46CRCh. 1 - Prob. 47CRCh. 1 - Prob. 48CRCh. 1 - Prob. 49CRCh. 1 - Prob. 50CRCh. 1 - Prob. 51CRCh. 1 - Prob. 52CRCh. 1 - Prob. 53CRCh. 1 - Prob. 54CRCh. 1 - Prob. 55CRCh. 1 - Prob. 56CRCh. 1 - Prob. 57CRCh. 1 - Prob. 58CRCh. 1 - Prob. 59CRCh. 1 - Prob. 60CRCh. 1 - Prob. 61CRCh. 1 - Prob. 62CRCh. 1 - Prob. 63CRCh. 1 - Prob. 64CRCh. 1 - Prob. 65CRCh. 1 - Prob. 66CRCh. 1 - Prob. 67CRCh. 1 - Prob. 68CRCh. 1 - Prob. 69CRCh. 1 - Prob. 70CRCh. 1 - Prob. 71CRCh. 1 - Prob. 72CRCh. 1 - Prob. 73CRCh. 1 - Prob. 74CRCh. 1 - Prob. 75CRCh. 1 - Prob. 76CRCh. 1 - Prob. 77CRCh. 1 - Prob. 78CRCh. 1 - Prob. 79CRCh. 1 - Prob. 80CRCh. 1 - Prob. 81CRCh. 1 - Prob. 82CRCh. 1 - Prob. 83CRCh. 1 - Prob. 84CRCh. 1 - Prob. 85CRCh. 1 - Prob. 86CRCh. 1 - Prob. 87CRCh. 1 - Prob. 88CRCh. 1 - Prob. 89CRCh. 1 - Prob. 90CRCh. 1 - Prob. 91CRCh. 1 - Prob. 92CRCh. 1 - Prob. 93CRCh. 1 - Prob. 94CRCh. 1 - Prob. 95CRCh. 1 - Prob. 96CRCh. 1 - Prob. 97CRCh. 1 - Prob. 98CRCh. 1 - Prob. 99CRCh. 1 - Prob. 100CRCh. 1 - Prob. 101CRCh. 1 - Prob. 102CRCh. 1 - Prob. 103CRCh. 1 - Prob. 104CRCh. 1 - Prob. 105CRCh. 1 - Prob. 106CRCh. 1 - Prob. 107CRCh. 1 - Prob. 108CRCh. 1 - Prob. 109CRCh. 1 - Prob. 110CRCh. 1 - Prob. 1CTCh. 1 - Prob. 2CTCh. 1 - Prob. 3CTCh. 1 - Prob. 4CTCh. 1 - Prob. 5CTCh. 1 - Prob. 6CTCh. 1 - Prob. 7CTCh. 1 - Prob. 8CTCh. 1 - Prob. 9CTCh. 1 - Prob. 10CTCh. 1 - Prob. 11CTCh. 1 - Prob. 12CTCh. 1 - Prob. 13CTCh. 1 - Prob. 14CTCh. 1 - Prob. 15CTCh. 1 - Prob. 16CTCh. 1 - Prob. 17CTCh. 1 - Prob. 18CTCh. 1 - Prob. 19CTCh. 1 - Prob. 20CT
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