Concept explainers
(a)
To graph: the data given in the table.
(a)

Explanation of Solution
Given data:
Table of year v/s Total enterprise value.
Graph:
Graph for the given table:
Year | Total enterprise value, V (in billions of dollars) |
2013 | 0.555 |
2014 | 0.750 |
2015 | 1.300 |
2016 | 1.900 |
2017 | 2.600 |
2018 | 3.100 |
Interpretation:
The value of enterprise increases with year.
(b)
To find: Linear regression of model
(b)

Answer to Problem 21E
Linear regression of model is
Explanation of Solution
Given data:
Table of year v/s Total enterprise value
Formula used:
Slope intercept form:
Calculation:
Linear regression of the model:
Conclusion:
Linear regression of model is
(c)
To find: Linear model is a good fit or not
(c)

Answer to Problem 21E
Yes it is a good fit.
Explanation of Solution
Given data:
Table of year v/s Total enterprise value
Calculation:
Yes this is a good fit because line of fit is having value nearly to original values.
Conclusion:
Yes it is a good fit.
(d)
Enterprise for 2021 and 2026
(d)

Answer to Problem 21E
Enterprise for 2021 will be 16.5 billion and for 2026 will be 19 billions
Explanation of Solution
Given data:
Table of year v/s Total enterprise value
Formula used:
Slope intercept form:
Calculation:
Enterprise for 2021 will be:
Enterprise for 2026 will be:
It is a reasonable answer because as the graph is increasing with year.
Conclusion:
Enterprise for 2021 will be 16.5 billion and for 2026 will be 19 billions
(e)
To find: The slope of graph.
(e)

Answer to Problem 21E
The slope model is 0.5.
Explanation of Solution
Given data:
Table of year v/s Total enterprise value
Formula used:
Slope intercept form:
Calculation:
Given model is:
Comparing with
The slope of model is 0.5 as the slope is positive so graph is increasing.
Conclusion:
The slope model is 0.5.
Chapter 1 Solutions
EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR
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