The monosaccharides used in the synthesis of nucleic acids are to be stated. Concept introduction: Carbohydrates are naturally occurring compounds. Carbohydrates are polyhydroxy aldehydes and ketones . A monosaccharide is the simplest form of carbohydrate. It possesses either ketone or aldehyde group with one or more than one hydroxyl groups. Disaccharides, trisaccharides, oligosaccharides, and polysaccharides all involve monosaccharide as subunits.

Question

5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3

Answer 1

Question

Chapter 17, Problem 17.36E

Interpretation Introduction

Interpretation:

The monosaccharides used in the synthesis of nucleic acids are to be stated.

Concept introduction:

Carbohydrates are naturally occurring compounds. Carbohydrates are polyhydroxy aldehydes and ketones.

A monosaccharide is the simplest form of carbohydrate. It possesses either ketone or aldehyde group with one or more than one hydroxyl groups. Disaccharides, trisaccharides, oligosaccharides, and polysaccharides all involve monosaccharide as subunits.

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5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3

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