Chemistry For Today: General, Organic, And Biochemistry, Loose-leaf Version
Chemistry For Today: General, Organic, And Biochemistry, Loose-leaf Version
9th Edition
ISBN: 9781305968707
Author: Spencer L. Seager
Publisher: Brooks Cole
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Chapter 17, Problem 17.13E
Interpretation Introduction

(a)

Interpretation:

The Fischer projections of 2, 3-dihydroxypropanoicacid for D and L isomers are to be drawn.

Concept introduction:

The Fischer projection is drawn by taking chiral carbons into consideration. The chiral carbons of the molecule are represented by the intersection of two lines in Fischer projection. The groups attached to the chiral carbon are attached to that intersection point. The D or L form is decided on the basis of the attachment of the hydroxyl group on the chiral carbon which is farthest from the carbonyl carbon. When the hydroxyl group is on right side, then it is D form. When the hydroxyl group is on left side, then it is L form.

Interpretation Introduction

(b)

Interpretation:

The Fischer projections of 2-chloro-3-hydroxypropanoicacid for D and L isomers are to be drawn.

Concept introduction:

The Fischer projection is drawn by taking chiral carbons into consideration. The chiral carbons of the molecule are represented by the intersection of two lines in Fischer projection. The groups attached to the chiral carbon are attached to that intersection point. The D or L form is decided on the basis of the attachment of the hydroxyl group on the chiral carbon which is farthest from the carbonyl carbon. When the hydroxyl group is on right side, then it is D form. When the hydroxyl group is on left side, then it is L form.

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Choose the Lewis structure for the compound below: H2CCHOCH2CH(CH3)2 HH H :d H H H C. Η H H HH H H H H. H H H HH H H H H H- H H H C-H H H HHHH
Each of the highlighted carbon atoms is connected to hydrogen atoms.
く Complete the reaction in the drawing area below by adding the major products to the right-hand side. If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area instead. Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge bonds. Just draw one molecule to represent each pair of enantiomers, using line bonds at the chiral center. More... No reaction. Explanation Check O + G 1. Na O Me Click and drag to start drawing a structure. 2. H + 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility 000 Ar P

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Chemistry For Today: General, Organic, And Biochemistry, Loose-leaf Version

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