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Concept explainers
(a)
Interpretation:
Dextrose is to be identified as a monosaccharide or a disaccharide. If it is a disaccharide, the individual monosaccharide components for dextrose are to be stated.
Concept introduction:
Monosaccharides are the small units of simple sugars. Disaccharides are formed by two units of monosaccharides. Polysaccharides are made up of small units of monosaccharides. These small units are joined together by glycoside linkage.
(b)
Interpretation:
Fructose is to be identified as a monosaccharide or a disaccharide. If it is a disaccharide, the individual monosaccharide components for fructose are to be stated.
Concept introduction:
Monosaccharides are the small units of simple sugars. Disaccharides are formed by two units of monosaccharides. Polysaccharides are made up of small units of monosaccharides. These small units are joined together by glycoside linkage.
(c)
Interpretation:
Sucrose is to be identified as a monosaccharide or a disaccharide. If it is a disaccharide, the individual monosaccharide components for dextrose are to be stated.
Concept introduction:
Monosaccharides are the small units of simple sugars. Disaccharides are formed by two units of monosaccharides. Polysaccharides are made up of small units of monosaccharides. These small units are joined together by glycoside linkage.
(d)
Interpretation:
Maltose is to be identified as a monosaccharide or a disaccharide. If it is a disaccharide, the individual monosaccharide components for maltose are to be stated.
Concept introduction:
Monosaccharides are the small units of simple sugars. Disaccharides are formed by two units of monosaccharides. Polysaccharides are made up of small units of monosaccharides. These small units are joined together by glycoside linkage.
(e)
Interpretation:
Lactose is to be identified as a monosaccharide or a disaccharide. If it is a disaccharide, the individual monosaccharide components for lactose are to be stated.
Concept introduction:
Monosaccharides are the small units of simple sugars. Disaccharides are formed by two units of monosaccharides. Polysaccharides are made up of small units of monosaccharides. These small units are joined together by glycoside linkage.
(f)
Interpretation:
Ribose is to be identified as a monosaccharide or a disaccharide. If it is a disaccharide, the individual monosaccharide components for ribose are to be stated.
Concept introduction:
Monosaccharides are the small units of simple sugars. Disaccharides are formed by two units of monosaccharides. Polysaccharides are made up of small units of monosaccharides. These small units are joined together by glycoside linkage.
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Chapter 17 Solutions
Chemistry For Today: General, Organic, And Biochemistry, Loose-leaf Version
- Could you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but (color-coded) and step by step so I can understand it better? Thank you! I want to see what they are doingarrow_forward
- Can you please help mne with this problem. Im a visual person, so can you redraw it, potentislly color code and then as well explain it. I know im given CO2 use that to explain to me, as well as maybe give me a second example just to clarify even more with drawings (visuals) and explanations.arrow_forwardPart 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff: Ag₂ CO3 = 2 Ag+ caq) + co} (aq) ksp = 8.10 × 10-12 Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5 a) which salt will precipitate first? (b) What % of the first anion precipitated will remain in the solution. by the time the second anion starts to precipitate? (c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate explanation per answerarrow_forwardPart 4. Butanoic acid (ka= 1.52× 10-5) has a partition coefficient of 3.0 (favors benzene) when distributed bet. water and benzene. What is the formal concentration of butanoic acid in each phase when 0.10M aqueous butanoic acid is extracted w❘ 25 mL of benzene 100 mL of a) at pit 5.00 b) at pH 9.00arrow_forward
- Calculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 Group of answer choices 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/molearrow_forwardCalculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 choices: 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/molearrow_forwardCalculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0arrow_forward
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