Chemistry For Today: General, Organic, And Biochemistry, Loose-leaf Version
9th Edition
ISBN: 9781305968707
Author: Spencer L. Seager
Publisher: Brooks Cole
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Question
Chapter 17, Problem 17.23E
Interpretation Introduction
Interpretation:
The Fischer projections of any aldotetrose and ketopentose are to be drawn.
Concept introduction:
A sugar can be classified on the basis of number of carbon atoms and can refer as triose, tetrose, pentose and hexose when it contains three, four, five and six carbon atoms respectively. A sugar whether it is aldos or ketos, depends on the presence of the
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Draw Haworth projection formulas for the a-anomer
of monosaccharides with each of the following Fischer
projection formulas.
a.
CHO
HOH
H-
HO-
H
-ОН
-Η
OH
CH₂OH
b.
CHO
H -OH
H
-ОН
HO
H
CH₂OH
1
Chapter 17 Solutions
Chemistry For Today: General, Organic, And Biochemistry, Loose-leaf Version
Ch. 17 - Prob. 17.1ECh. 17 - Describe whether each of the following substances...Ch. 17 - Prob. 17.3ECh. 17 - Prob. 17.4ECh. 17 - Prob. 17.5ECh. 17 - Why are carbon atoms 1 and 3 of glyceraldehyde not...Ch. 17 - Prob. 17.7ECh. 17 - Which of the following molecules can have...Ch. 17 - Which of the following molecules can have...Ch. 17 - Prob. 17.10E
Ch. 17 - Prob. 17.11ECh. 17 - Prob. 17.12ECh. 17 - Prob. 17.13ECh. 17 - Draw Fischer projections for both the D and L...Ch. 17 - Prob. 17.15ECh. 17 - Prob. 17.16ECh. 17 - Prob. 17.17ECh. 17 - Prob. 17.18ECh. 17 - Prob. 17.19ECh. 17 - Prob. 17.20ECh. 17 - Prob. 17.21ECh. 17 - Prob. 17.22ECh. 17 - Prob. 17.23ECh. 17 - Prob. 17.24ECh. 17 - Prob. 17.25ECh. 17 - Prob. 17.26ECh. 17 - Prob. 17.27ECh. 17 - Prob. 17.28ECh. 17 - Prob. 17.29ECh. 17 - Prob. 17.30ECh. 17 - Prob. 17.31ECh. 17 - Prob. 17.32ECh. 17 - Prob. 17.33ECh. 17 - Prob. 17.34ECh. 17 - Prob. 17.35ECh. 17 - Prob. 17.36ECh. 17 - Prob. 17.37ECh. 17 - Prob. 17.38ECh. 17 - Prob. 17.39ECh. 17 - Prob. 17.40ECh. 17 - Prob. 17.41ECh. 17 - Prob. 17.42ECh. 17 - Prob. 17.43ECh. 17 - Prob. 17.44ECh. 17 - Prob. 17.45ECh. 17 - Prob. 17.46ECh. 17 - Prob. 17.47ECh. 17 - Sucrose and honey are commonly used sweeteners....Ch. 17 - Prob. 17.49ECh. 17 - Prob. 17.50ECh. 17 - Prob. 17.51ECh. 17 - Prob. 17.52ECh. 17 - Prob. 17.53ECh. 17 - Prob. 17.54ECh. 17 - Prob. 17.55ECh. 17 - Prob. 17.56ECh. 17 - Prob. 17.57ECh. 17 - Prob. 17.58ECh. 17 - Prob. 17.59ECh. 17 - Prob. 17.60ECh. 17 - Prob. 17.61ECh. 17 - Prob. 17.62ECh. 17 - Prob. 17.63ECh. 17 - Prob. 17.64ECh. 17 - Prob. 17.65ECh. 17 - Prob. 17.66ECh. 17 - Prob. 17.67ECh. 17 - Prob. 17.68ECh. 17 - Prob. 17.69ECh. 17 - Prob. 17.70ECh. 17 - Prob. 17.71ECh. 17 - Prob. 17.72ECh. 17 - Prob. 17.73ECh. 17 - Glucose is a reducing sugar, which if boiled in...Ch. 17 - Prob. 17.75E
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- Draw the Fischer projection of a D-ketotetrose. Click and drag to start drawing a structure. X MAarrow_forwardDraw the a anomer of the cyclic form of this monosaccharide. H HO-C-H H-C-OH HO-C-H H-C-OH CH₂OH Click and drag to start drawing a structure. D U X E Carrow_forwardDraw a Haworth project of a common cyclic form of this monosaccharide:arrow_forward
- a) Draw Haworth projections of both - and -anomers of D-fructose. Indicate which carbon is the anomeric carbon.b) Sucrose is a disaccharide made up of a molecule of D-fructose and D-glucose. Draw the structure of sucrose clearly indicating the linkage between the two monosaccharides and its biological significance.c) Tollen’s reagent is a very mild oxidizing agent which normally oxidize aldehydes but not ketones. However, both glucose and fructose give positive results with Tollen’s reagent and are classified as reducing sugars. Explain how fructose can also give positive results with Tollen’s reagent (illustrate using structures).arrow_forwardDraw a Fischer Projection formula for the enantiomer of each of the following monosaccharides.arrow_forward1. Which of the following is not true to the monosaccharide below? H. ОН но- -H- но ОН ĆH2OH O It is the Fischer Projection of D-glucose. It is an aldohexose having 4 chiral centers and 24 stereoisomers. It is has a D-glucose because OH- group bonded to the highest numbered chiral C is pointing to the right. It is a polyhydroxy ketone having 8 enantiomeric pair.arrow_forward
- Assign a name to each monosaccharide (Include if it's an alpha or beta and if it's a D or L)arrow_forwardLactose is a disaccharide composed of a 1-4 glycosidic bondbetween galactose and glucose.A) Is lactose a reducing sugar? B) Label the glucose and galactose rings on the lactose structure to theright. C) Circle the anomeric positions. Circle oneThe anomeric position of the acetal is Alpha BetaThe anomeric position of the hemiacetal is Alpha BetaD) What is the relationship between glucose and galactose? E) Give a specific acid mechanism hydrolyzing lactose into glucoseand galactose. Show lone pairs on the oxygen atoms directly involved in each step, show formal charges, correctly use arrows, and do not skip steps.arrow_forward3) Name the following monosaccharide to indicate its carbonyl group and the number of carbon atoms. a) 2-ketopentose b) 3-ketoheptose c) 2-aldopentose d) 3-aldohexose HOHHH HO-C-C-C-C-C-OH H OH OH Harrow_forward
- Draw the product formed when each monosaccharide is oxidized with Benedict’s reagent.arrow_forward18. Draw the Fischer projection of L-galactose.arrow_forwardBe sure to answer all parts. The Fischer projection of D-glucose is shown below. Draw its mirror image as a Fischer projection. CHO OH HO H. draw structure... H. OH H. OH CH,OHarrow_forward
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