Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Textbook Question
Chapter 17, Problem 10P
You are a genetic counselor, and several members of the family whose pedigree for an inherited disorder is depicted in Genetic Analysis
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Below is a pedigree of a family, some of whom have the autosomal dominant condition Huntington's disease.
Affected individuals are indicated by a dark square or circle. The male in generation I (indicated by the arrow) is
heterozygous for the Huntington's disease mutation.
The following two questions relate to this pedigree.
Generation
II
II
If H represents the disease allele, and h the wild type allele, what is the genotype of the individual indicated by the
*?
Select one alternative:
O hh
O Hh
O hH
O HH
1-Gigantism is being traced in a family through a pedigree. Its mode of inheritance is thought to be autosomal recessive.
You examine the pedigree and decide that the mode of inheritance is not correct. What is the correct mode of inheritance?
2-Provide 2 pieces of evidence for the mode of inheritance selected for Gigantism. (i.e.- Individual 45 is afflicted and passed it on to all of her offspring, indicating that it is dominant. Or there is a gendered pattern of inheritance seen when Individual 99 passed it on to only his female offspring.)
Chapter 17 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. 17 - 17.1 Reciprocal crosses of experimental animals or...Ch. 17 - 17.2 How are some of the characteristics of the...Ch. 17 - 17.3 The human mitochondrial genome encodes...Ch. 17 - What is the evidence that transfer of DNA from the...Ch. 17 - Draw a graph depicting the relative amounts of...Ch. 17 - Prob. 6PCh. 17 - 17.7 What is the evidence that the ancient...Ch. 17 - 17.8 Outline the steps required for a gene...Ch. 17 - 17.9 Consider the phylogenetic tree presented in...Ch. 17 - You are a genetic counselor, and several members...
Ch. 17 - A mutation in Arabidopsis immutans results in the...Ch. 17 - What type or types of inheritance are consistent...Ch. 17 - You have isolated (1) a streptomycin-resistant...Ch. 17 - You have isolated two petite mutants, pet1 and...Ch. 17 - 17.15 Consider this human pedigree for a vision...Ch. 17 - A 50- year - old man has been diagnosed with MELAS...Ch. 17 - 17.17 The first person in a family to exhibit...Ch. 17 - Prob. 18PCh. 17 - 17.19 What is the most likely mode of inheritance...Ch. 17 - 17.20 In , the Russian Tsar Nicholaswas deposed,...Ch. 17 - 17.21 The dodo bird (Raphus cucullatus) lived on...Ch. 17 - Cytoplasmic male sterility (CMS) in plants has...Ch. 17 - 17.23 Wolves and coyotes can interbreed in...Ch. 17 - Prob. 24PCh. 17 - Prob. 25PCh. 17 - Most large protein complexes in mitochondria and...Ch. 17 - As described in this chapter, mothers will pass on...
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- Normal wife Affected husband As a genetic counsellor you are presented with a married couple where one of them has a family history of this disease. The husband is affected by this disease and the wife is normal. The couple, who are thinking of starting a family, would like to know what their chances are of having a child born with this condition. They would also like to know what the probabilities are of having an affected boy or affected girl. Use the symbols above to complete the diagram right and determine the probabilities stated below (expressed as a proportion or percentage). Parents 4. Determine the probability of having: Gametes (a) Affected children: Possible (b) An affected girl: fertilizations (c) An affected boy: O O O O Children Affected aite if 耳arrow_forward17arrow_forward3.23 The following pedigree shows the inheritance of a reces- sive trait. Unless there is evidence to the contrary, assume that the individuals who have married into the family do not carry the recessive allele. What is the chance that the offspring of the following matings will show the trait: (a) III-1 × III-12; (b) II-4 × III-14; (c) III-6 × III-13; (d) IV-1 X IV-2? I || III 2 2 3 4 LO 5 3 6 7 8 1 1 2 9 10 2 5 6 7 8 11 12 13 14 15 16 17arrow_forward
- A heterozygous pea plant produces violet flowers and yellow, round seeds. Describe the expected genotypes of the gametes produced by Mendelian inheritance. If all three genes are found on the same arm of one chromosome should a scientist predict that inheritance patterns will follow Mendelian genetics?arrow_forwardAs a physician, you deliver a baby with protruding heels and clenched fists with the second and fifth fingers over-lapping the third and fourth fingers. a. What genetic disorder do you suspect the baby has? b. How do you confirm your suspicion?arrow_forwardWhy is it more efficient to perform a test cross with a homozygous recessive donor than a homozygous dominant donor? How could the same information still he found with a homozygous dominant donor?arrow_forward
- A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?arrow_forwardA couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?arrow_forwardA couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What if the couple wanted prenatal testing so that a normal fetus could be aborted?arrow_forward
- Explain why it was essential that Mendel perform his crosses using a large sample size?arrow_forwardOnly need help with 1 D and 2 Darrow_forwardA 20-year-old woman comes to your genetic counselling center because she knows that Huntington disease occurs in members of her family. Huntington is an autosomal dominant disease that often becomes apparent around 35–40 years of age. Her paternal grandfather was afflicted, but so far her 41 year old father shows no symptoms. Her two great-great grandmothers on her father's side were healthy well into their 90s, and one of her great-great grandfathers died of unknown causes at 45. Testing for Huntington disease is extremely expensive, but she is concerned that she may fall victim to this disease and wants to plan her life accordingly. After examining her pedigree you advise her to: not get tested because her father is only a carrier and it is very unlikely her mother is a carrier. not get tested because there is no possibility that she is homozygous. get tested because her father could be a carrier. not get tested because only males in her family get the disease. not get tested…arrow_forward
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