Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 17, Problem 17P
The first person in a family to exhibit Leber hereditary optic neuropathy (LHON) was
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This is a typical pedigree for a family that carries neurofibromatosis.
Is individual I-2 most likely homozygous or heterozygous? Why? Explain.
Explain why it is possible for the proband in the following pedigree to have children of blood types A, B, and AB. Considering epistatic genes, what are the possible genotypes of II-2?
Shown below is a pedigree for Phenylketonuria (PKU), an autosomal recessive metabolic disorder. The characteristic feature of PKU is severe mental retardation
A) What is the probability that individual II-1 is heterozygous for this gene?
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C) If individuals III-3 and III-4 were to marry, what is the probability that their child would express PKU?
Chapter 17 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. 17 - 17.1 Reciprocal crosses of experimental animals or...Ch. 17 - 17.2 How are some of the characteristics of the...Ch. 17 - 17.3 The human mitochondrial genome encodes...Ch. 17 - What is the evidence that transfer of DNA from the...Ch. 17 - Draw a graph depicting the relative amounts of...Ch. 17 - Prob. 6PCh. 17 - 17.7 What is the evidence that the ancient...Ch. 17 - 17.8 Outline the steps required for a gene...Ch. 17 - 17.9 Consider the phylogenetic tree presented in...Ch. 17 - You are a genetic counselor, and several members...
Ch. 17 - A mutation in Arabidopsis immutans results in the...Ch. 17 - What type or types of inheritance are consistent...Ch. 17 - You have isolated (1) a streptomycin-resistant...Ch. 17 - You have isolated two petite mutants, pet1 and...Ch. 17 - 17.15 Consider this human pedigree for a vision...Ch. 17 - A 50- year - old man has been diagnosed with MELAS...Ch. 17 - 17.17 The first person in a family to exhibit...Ch. 17 - Prob. 18PCh. 17 - 17.19 What is the most likely mode of inheritance...Ch. 17 - 17.20 In , the Russian Tsar Nicholaswas deposed,...Ch. 17 - 17.21 The dodo bird (Raphus cucullatus) lived on...Ch. 17 - Cytoplasmic male sterility (CMS) in plants has...Ch. 17 - 17.23 Wolves and coyotes can interbreed in...Ch. 17 - Prob. 24PCh. 17 - Prob. 25PCh. 17 - Most large protein complexes in mitochondria and...Ch. 17 - As described in this chapter, mothers will pass on...
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- Which members of the pedigree could have been carriers, and which might have been the source of the mutation?arrow_forwardThis pedigree depicts the inheritance of the mitochondrial disease Leber hereditary optic neuropathy (LHON). Individual I-1 does not show any symptoms of LHON, whereas her daughter and all three of her grandchildren are affected. Provide two explanations for this.arrow_forwardThe pedigree below shows the phenotypes of the ABO blood groups and Rhesus factors [positive (+) and negative (-)] for several members of a family. I (B+ AB- 1 2 3 4 II O- A+ В- B- AB+ A+ 1 2 4 5 6 a. What are the ABO blood group genotypes of individuals I-1 and I-2? b. Which child/ren of individual I-4 can donate blood to him? c. Which individual in the pedigree can donate blood to all the other individuals in the pedigree?arrow_forward
- Chands syndrome is an autosomal recessive condition characterized by very curly hair, underdeveloped nails, and abnormally shaped eyelids. In the pedigree below: Which individuals must be carriers (heterozygotes)? ----- arrow_forwardBrachydactyly type D is human autosomal dominant condition in which the thumbs are abnormally short and broad. In most cases, both thumbs are affected, but occasionally just one thumb is involved. The pedigree above shows a family in which brachydactlyly type D is segregating. Filled circles and squares represent females and males who have involvement of both thumbs. Half-filled in symbols represent family members with just one thumb affected? (Picture attached) There is evidence of variable expressivity and incomplete penetrance in this family. Which individual is most likely nonpenetrant for the trait? A) III-11 B) IV-1 C) IV-5 D) III-10 E) II-4arrow_forwardThis pedigree consist of cystic fibrosis that is an inherited disease caused by f a recessive allele. Find the genotypes of X and M? Given: O normal female □ normal male ◍ cystic fibrosis female ▨ cystic fibrosis male A) M= Ff X=Ff B) M=Ff X=ff C) M=ff X=ff D) M=ff X=FFarrow_forward
- The attached image is a pedigree of a family with a history of sickle cell anemia (the individuals with the filled-in symbols have the disease and no new mutations are occurring in any individual). Sickle cell anemia is inherited in an autosomal recessive manner. What is the probability that the individual with the question mark (?) will get the disease? a) 1/4 b) 1/2 c) 2/3 d) 1arrow_forwardShown below is a pedigree for a completely penetrant trait called Adams syndrome in which babies are born blind. This trait occurs when an allele of the adams gene is associated with ≥200 tandem trinucleotide repeats (the normal number is 10). First cousins, III-1 and III-2 married and their first child (IV-1) was blind. For their next child, they decided to do in vitro fertilization with III-1's sperm and III-2's eggs to generate six embryos (labeled E1-6). When each embryo contained eight cells, a single cell was removed and genomic DNA was isolated. PCR reactions using primers that flank the trinucleotide repeat region were then performed and the resulting fragments were fractionated on an agarose gel. PCR reactions using genomic DNA from III-1, III-2 and IV-1 were included as controls. The DNA was visualized using a fluorescent dye and the gel is shown below. Based on this information, select the best answer from the list to the questions below. || E1 = embryo 1 IV E1 E2 E3 E4 E5…arrow_forwardTake the example of B-thalassemia, an autosomal recessive genetic disease that particularly affects people from around the Mediterranean. This disease is associated with an anomaly of hemoglobin, a protein essential for the transport of oxygen, which is composed of four chains: two alpha (a) and two beta (B). In case of B-thalassemia, the ẞ chains are produced in insufficient or no quantity in an individual homozygous recessive resulting in insufficient production of overall hemoglobin leading to anemia and other physiological challenges. The gene that controls the synthesis of the ẞ chains is located on chromosome 11. Here is part of the coding portion of this gene (which controls a total of 146 amino acids and of which you only see the portion 36 to 41) and one of the targeted mutations: 1. Give the sequence of amino acids from the template and mutated strands. 2. What type of point mutation is it? 3. Using the principles of the theory of evolution, explain briefly and generally why…arrow_forward
- In the pedigree below, male II-1 has Klinefelter syndrome, which is the result of an XXY karyotype. On the X chromosome, a gene called G6PD has two codominant alleles, G6PDA and G6PDB. In this pedigree, A, B, and AB refer to the phenotypes associated with the alleles of this gene. (Note: In this family, no individuals have the AB version of the phenotype.) A A B Based on the information in the pedigree, when could nondisjunction have occurred? Select all correct answers. In Il-1's father, during meiosis I In II-1's mother, during meiosis I In II-1's mother, during meiosis II In Il-1's father, during meiosis IIarrow_forwardThe following pedigree represents the inheritance of an autosomal recessive disease in a certain family. 2 5 2 4 5 8 3 4. 6. 1 1- How many males are affected by the disease? 3- How many children did the couple Il-4 and Il-5 have? 4- How many sisters did III-8 have? 5- What is the genotype of III-8? 40arrow_forwardThe pedigree below shows three generations of a family that carries albinism, an autosomal recessive genetic disease. In the third generation, a child was born with albinism but the genotypes of the rest of the family are unknown. No other family members have the disease. Assume normal, Mendelian genetics with no new mutations. What are the genotypes of the parents of the affected child? A) There is not enough information to determine their genotypes B) Both are homozygous for albinism C) One is hemizygous and one is heterozygous for albinism D) Both are heterozygous for albinism E) One is homozygous and one is heterozygous for abinismarrow_forward
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