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(a)
Interpretation:
From the given pair, the more reactive ketone has to be identified.
Concept introduction:
The relative reactivity of carbonyl groups:
Carbonyl group is polar because oxygen is more electronegative than the carbon. As results carbonyl group is an electron deficient and it is an electrophile.
An
The
(b)
Interpretation:
From the given pair, the more reactive ketone has to be identified.
Concept introduction:
The relative reactivity of carbonyl groups:
Carbonyl group is polar because oxygen is more electronegative than the carbon. As results carbonyl group is an electron deficient and it is an electrophile.
An aldehyde has a greater partial positive charge on its carbonyl carbon than a ketone because an alkyl group is more electrons donating than hydrogen.
The ketones with small alkyl groups bonded to the carbonyl carbon are more reactive than those with large alkyl groups.
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Chapter 16 Solutions
EBK ORGANIC CHEMISTRY
- 3) Propagation of uncertainty. Every measurement has uncertainty. In this problem, we'll evaluate the uncertainty in every step of a titration of potassium hydrogen phthalate (a common acid used in titrations, abbreviated KHP, formula CsH5KO4) with NaOH of an unknown concentration. The calculation that ultimately needs to be carried out is: concentration NaOH 1000 x mass KHP × purity KHP molar mass KHP x volume NaOH Measurements: a) You use a balance to weigh 0.3992 g of KHP. The uncertainty is ±0.15 mg (0.00015 g). b) You use a buret to slowly add NaOH to the KHP until it reaches the endpoint. It takes 18.73 mL of NaOH. The uncertainty of the burst is 0.03 mL.. c) The manufacturer states the purity of KHP is 100%±0.05%. d) Even though we don't think much about them, molar masses have uncertainty as well. The uncertainty comes from the distribution of isotopes, rather than random measurement error. The uncertainty in the elements composing KHP are: a. Carbon: b. Hydrogen: ±0.0008…arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardHow would you use infrared spectroscopy to distinguish between the following pairs of constitutional isomers? (a) CH3C=CCH3 || and CH3CH2C=CH (b) CH3CCH=CHCH3 and CH3CCH2CH=CH2 Problem 12-41 The mass spectrum (a) and the infrared spectrum (b) of an unknown hydrocarbon are shown. Propose as many structures as you can. (a) 100 Relative abundance (%) 80 60 60 40 200 20 (b) 100 Transmittance (%) 10 20 20 80- 60- 40- 20 40 60 80 100 120 140 m/z 500 4000 3500 3000 2500 2000 1500 Wavenumber (cm-1) 1000arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
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