In naming of carboxylic acids using IUPAC system, the carboxyl atom is always assigned which number has to be chosen from the given options. Concept Introduction: For naming a carboxylic acid in IUPAC nomenclature , the suffix “-oic” is added to the parent alkane name. IUPAC rules for naming a carboxylic acid: The longest parent carbon chain is identified that includes the carboxyl group. The parent chain name is changed by replacing the suffix “-e” with “-oic acid”. Numbering is done in a way that the carboxyl group is designated as number 1. This is not indicated in the part of the name because for carboxylic acid, the carboxyl carbon is always numbered 1. The identity and location of substituents if any has to be determined and this information has to be added in front of the IUPAC name. If the carboxyl functional group is attached to a ring of carbon atoms, the ring is named and “-carboxylic acid” is added as suffix.

Question

Want to see the full answer?

Answer 1

Question

Chapter 16.2, Problem 1QQ

Interpretation Introduction

Interpretation:

In naming of carboxylic acids using IUPAC system, the carboxyl atom is always assigned which number has to be chosen from the given options.

Concept Introduction:

For naming a carboxylic acid in IUPAC nomenclature, the suffix “-oic” is added to the parent alkane name.

IUPAC rules for naming a carboxylic acid:

The longest parent carbon chain is identified that includes the carboxyl group.

The parent chain name is changed by replacing the suffix “-e” with “-oic acid”.

Numbering is done in a way that the carboxyl group is designated as number 1. This is not indicated in the part of the name because for carboxylic acid, the carboxyl carbon is always numbered 1.

The identity and location of substituents if any has to be determined and this information has to be added in front of the IUPAC name.

If the carboxyl functional group is attached to a ring of carbon atoms, the ring is named and “-carboxylic acid” is added as suffix.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Experiment 27 hates & Mechanisms of Reations Method I visual Clock Reaction A. Concentration effects on reaction Rates Iodine Run [I] mol/L [S₂082] | Time mo/L (SCC) 0.04 54.7 Log 1/ Time Temp Log [ ] 13,20] (time) / [I] 199 20.06 23.0 30.04 0.04 0.04 80.0 22.8 45 40.02 0.04 79.0 21.6 50.08 0.03 51.0 22.4 60-080-02 95.0 23.4 7 0.08 0-01 1970 23.4 8 0.08 0.04 16.1 22.6

(15 pts) Consider the molecule B2H6. Generate a molecular orbital diagram but this time using a different approach that draws on your knowledge and ability to put concepts together. First use VSEPR or some other method to make sure you know the ground state structure of the molecule. Next, generate an MO diagram for BH2. Sketch the highest occupied and lowest unoccupied MOs of the BH2 fragment. These are called frontier orbitals. Now use these frontier orbitals as your basis set for producing LGO's for B2H6. Since the BH2 frontier orbitals become the LGOS, you will have to think about what is in the middle of the molecule and treat its basis as well. Do you arrive at the same qualitative MO diagram as is discussed in the book? Sketch the new highest occupied and lowest unoccupied MOs for the molecule (B2H6).

Q8: Propose an efficient synthesis of cyclopentene from cyclopentane.