
Concept explainers
(a)
Interpretation:
The product for the reaction of ethylbenzene with bromine gas and
Concept introduction:
An electrophilic

Answer to Problem 16.35AP
No product will be formed in the reaction of ethylbenzene with bromine gas and
Explanation of Solution
Ethylbenzene is ortho and para directing group, the electrophile will substitute on either ortho or para position of the benzene ring. In the dark no bromine free radical will be generated, therefore, no free radical reaction will occur. Carbon tetrachloride does not facilitate the production of positively charged
No reaction takes place between ethylbenzene with bromine gas and
(b)
Interpretation:
The product for the reaction ethylbenzene with
Concept introduction:
An electrophilic aromatic substitution reaction is a type of reaction in which an electrophile substitutes a hydrogen atom of the aromatic ring. Aromatic ring does not easily undergo nucleophilic substitution reaction; however, it undergoes electrophilic substitution reaction easily.

Answer to Problem 16.35AP
The products for the reaction ethylbenzene with
Explanation of Solution
Ethylbenzene is ortho and para directing group, the electrophile will substitute on either ortho or para position of the benzene ring. The nitronium ion
The corresponding
Figure 1
The products for the reaction ethylbenzene with
(c)
Interpretation:
The product for the reaction ethylbenzene with concentrated
Concept introduction:
An electrophilic aromatic substitution reaction is a type of reaction in which an electrophile substitutes a hydrogen atom of the aromatic ring. Aromatic ring does not easily undergo nucleophilic substitution reaction; however, it undergoes electrophilic substitution reaction easily.

Answer to Problem 16.35AP
The products for the reaction ethylbenzene with concentrated
Explanation of Solution
Ethylbenzene is ortho and para directing group, the electrophile will substitute on either ortho or para position of the benzene ring. In the presence of concentrated sulphuric acid, the
Figure 2
The products for the reaction ethylbenzene with concentrated
(d)
Interpretation:
The product for the reaction ethylbenzene with propionyl chloride and
Concept introduction:
Friedel Craft acylation is an electrophilic aromatic substitution reaction. In this reaction, the synthesis of the monoacylated product takes place from the reaction between aromatic rings and acyl chlorides.

Answer to Problem 16.35AP
The products for the reaction of ethylbenzene with propionyl chloride and
Explanation of Solution
Friedel-Crafts alkylation permits the synthesis of alkylated products by the reaction of arenes with alkyl chlorides in the presence of aluminum chloride (Lewis acid). This alkylation reaction comes under the category of electrophilic aromatic substitution. Ethylbenzene is ortho and para directing group, the electrophile will substitute on either ortho or para position of the benzene ring. The acyl group attacks either ortho or para position of ethylbenzene to form the product. The corresponding chemical reaction is shown below.
Figure 3
The products for the reaction ethylbenzene with propionyl chloride and
(e)
Interpretation:
The product for the exothermic reaction of ethylbenzene with
Concept introduction:
An electrophilic aromatic substitution reaction is a type of reaction in which an electrophile substitutes a hydrogen atom of the aromatic ring. Aromatic ring does not easily undergo nucleophilic substitution reaction; however, it undergoes electrophilic substitution reaction easily.

Answer to Problem 16.35AP
The product for the exothermic reaction of ethylbenzene with
Explanation of Solution
Ethylbenzene is ortho and para directing group, the electrophile will substitute on either ortho or para position of the benzene ring. In the presence of
Figure 4
The product for the exothermic reaction of ethylbenzene with
(f)
Interpretation:
The product for the exothermic reaction of ethylbenzene with bromine gas and
Concept introduction:
An electrophilic aromatic substitution reaction is a type of reaction in which an electrophile substitutes a hydrogen atom of the aromatic ring. Aromatic ring does not easily undergo nucleophilic substitution reaction; however, it undergoes electrophilic substitution reaction easily.

Answer to Problem 16.35AP
The products for the exothermic reaction of ethylbenzene with bromine gas and
Explanation of Solution
Ethylbenzene is ortho and para directing group, the electrophile will substitute on either ortho or para position of the benzene ring. In this reaction, positively charged
Figure 5
The products for the exothermic reaction ethylbenzene with bromine gas and
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Chapter 16 Solutions
Organic Chemistry Study Guide and Solutions
- For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. དྲ。 ✗MgBr ? O CI Will the first product that forms in this reaction create a new C-C bond? Yes No • ? Will the first product that forms in this reaction create a new CC bond? Yes No × : ☐ Xarrow_forwardPredict the major products of this organic reaction: OH NaBH4 H ? CH3OH Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. ☐ : Sarrow_forwardPredict the major products of this organic reaction: 1. LIAIHA 2. H₂O ? Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. X : ☐arrow_forward
- For each reaction below, decide if the first stable organic product that forms in solution will create a new C - C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 tu ? ? OH Will the first product that forms in this reaction create a new CC bond? Yes No Will the first product that forms in this reaction create a new CC bond? Yes No C $ ©arrow_forwardAs the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C-C bond as its major product: 1. MgCl ? 2. H₂O* If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new CC bond. G marrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M NH4 Ksp Hg2Br2 = 5.6×10-23.arrow_forward
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- 3-Oxo-butanenitrile and (E)-2-butenal are mixed with sodium ethoxide in ethanol. Draw and name the structures of the products.arrow_forwardWhat is the reason of the following(use equations if possible) a.) In MO preperation through diazotization: Addition of sodium nitrite in acidfied solution in order to form diazonium salt b.) in MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at low pH c.) In MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at pH 4.5 d.) Avoiding not cooling down the reaction mixture when preparing the diazonium salt e.) Cbvcarrow_forwardA 0.552-g sample of an unknown acid was dissolved in water to a total volume of 20.0 mL. This sample was titrated with 0.1103 M KOH. The equivalence point occurred at 29.42 mL base added. The pH of the solution at 10.0 mL base added was 3.72. Determine the molar mass of the acid. Determine the Ka of the acid.arrow_forward
