Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
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Question
Chapter 15, Problem 6STP
Interpretation Introduction
Interpretation: To explain the reason for similar conductivities between two pairs of conducting solutions.
Concept Introduction: Conductivity is defined as the ability of an electrolyte or a solute to conduct electricity. Not all the solutions need to conduct electricity as all the solutions are not electrolytes. Therefore, only the solutions which can dissociate can participate in conduction.
Expert Solution & Answer
Answer to Problem 6STP
As both solutions will produce the same number of ions in the solution.
Explanation of Solution
When two pairs of conducting solutions are considered, similar conductivity is possible only when the number of ions that are produced upon dissociation in both the solutions. Only if there are the same number of ions in both solutions, there is a possibility for similar conductivities.
Conclusion
When there are a greater number of free electrons, then the conductivity will be good. The conductivity is purely based on the number of ions that are present in the solution. When there are no ions in the solution, the conductivity will be nil.
Chapter 15 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
Ch. 15.1 - Prob. 1LCCh. 15.1 - Prob. 2LCCh. 15.1 - Prob. 3LCCh. 15.1 - Prob. 4LCCh. 15.1 - Prob. 5LCCh. 15.1 - Prob. 6LCCh. 15.1 - Prob. 7LCCh. 15.2 - Prob. 8SPCh. 15.2 - Prob. 9SPCh. 15.2 - Prob. 10LC
Ch. 15.2 - Prob. 11LCCh. 15.2 - Prob. 12LCCh. 15.2 - Prob. 13LCCh. 15.2 - Prob. 14LCCh. 15.2 - Prob. 15LCCh. 15.2 - Prob. 16LCCh. 15.2 - Prob. 17LCCh. 15.3 - Prob. 18LCCh. 15.3 - Prob. 19LCCh. 15.3 - Prob. 20LCCh. 15.3 - Prob. 21LCCh. 15.3 - Prob. 22LCCh. 15.3 - Prob. 23LCCh. 15 - Prob. 24ACh. 15 - Prob. 25ACh. 15 - Prob. 26ACh. 15 - Prob. 27ACh. 15 - Prob. 28ACh. 15 - Prob. 29ACh. 15 - Prob. 30ACh. 15 - Prob. 31ACh. 15 - Prob. 32ACh. 15 - Prob. 33ACh. 15 - Prob. 34ACh. 15 - Prob. 35ACh. 15 - Prob. 36ACh. 15 - Prob. 37ACh. 15 - Prob. 38ACh. 15 - Prob. 39ACh. 15 - Prob. 40ACh. 15 - Prob. 41ACh. 15 - Prob. 42ACh. 15 - Prob. 43ACh. 15 - Prob. 44ACh. 15 - Prob. 45ACh. 15 - Prob. 46ACh. 15 - Prob. 47ACh. 15 - Prob. 48ACh. 15 - Prob. 49ACh. 15 - Prob. 50ACh. 15 - Prob. 51ACh. 15 - Prob. 52ACh. 15 - Prob. 53ACh. 15 - Prob. 54ACh. 15 - Prob. 55ACh. 15 - Prob. 56ACh. 15 - Prob. 57ACh. 15 - Prob. 58ACh. 15 - Prob. 59ACh. 15 - Prob. 60ACh. 15 - Prob. 61ACh. 15 - Prob. 62ACh. 15 - Prob. 63ACh. 15 - Prob. 64ACh. 15 - Prob. 65ACh. 15 - Prob. 66ACh. 15 - Prob. 67ACh. 15 - Prob. 68ACh. 15 - Prob. 69ACh. 15 - Prob. 70ACh. 15 - Prob. 71ACh. 15 - Prob. 72ACh. 15 - Prob. 73ACh. 15 - Prob. 74ACh. 15 - Prob. 75ACh. 15 - Prob. 76ACh. 15 - Prob. 77ACh. 15 - Prob. 78ACh. 15 - Prob. 79ACh. 15 - Prob. 80ACh. 15 - Prob. 81ACh. 15 - Prob. 82ACh. 15 - Prob. 83ACh. 15 - Prob. 84ACh. 15 - Prob. 85ACh. 15 - Prob. 86ACh. 15 - Prob. 87ACh. 15 - Prob. 88ACh. 15 - Prob. 89ACh. 15 - Prob. 90ACh. 15 - Prob. 91ACh. 15 - Prob. 92ACh. 15 - Prob. 93ACh. 15 - Prob. 94ACh. 15 - Prob. 95ACh. 15 - Prob. 96ACh. 15 - Prob. 97ACh. 15 - Prob. 98ACh. 15 - Prob. 99ACh. 15 - Prob. 100ACh. 15 - Prob. 101ACh. 15 - Prob. 102ACh. 15 - Prob. 103ACh. 15 - Prob. 104ACh. 15 - Prob. 105ACh. 15 - Prob. 106ACh. 15 - Prob. 107ACh. 15 - Prob. 108ACh. 15 - Prob. 109ACh. 15 - Prob. 110ACh. 15 - Prob. 111ACh. 15 - Prob. 1STPCh. 15 - Prob. 2STPCh. 15 - Prob. 3STPCh. 15 - Prob. 4STPCh. 15 - Prob. 5STPCh. 15 - Prob. 6STPCh. 15 - Prob. 7STPCh. 15 - Prob. 8STPCh. 15 - Prob. 9STPCh. 15 - Prob. 10STP
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