Electric potential The potential function for the force field due to a charge q at the origin is φ = 1 4 π ε 0 q | r | , where r = 〈 x , y , z 〉 is the position vector of a point in the field and ε 0 is the permittivity of free space. a. Compute the force field F = – ▿ φ b. Show that the field is irrotational; that is ▿ × F = 0.
Electric potential The potential function for the force field due to a charge q at the origin is φ = 1 4 π ε 0 q | r | , where r = 〈 x , y , z 〉 is the position vector of a point in the field and ε 0 is the permittivity of free space. a. Compute the force field F = – ▿ φ b. Show that the field is irrotational; that is ▿ × F = 0.
Solution Summary: The author explains the force field F=-nabla phi , where the position vector of r=langle x,y,zrangle is the permitivity of the free
Electric potential The potential function for the force field due to a charge q at the origin is
φ
=
1
4
π
ε
0
q
|
r
|
, where r = 〈x, y, z〉 is the position vector of a point in the field and ε0 is the permittivity of free space.
a. Compute the force field F = – ▿φ
b. Show that the field is irrotational; that is ▿ × F = 0.
Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.
Assuming that the rate of change of the price P of a certain commodity is proportional to the difference between demand D and supply S at any time t, the differential equations describing the price fluctuations with respect to time can be expressed as: dP/dt = k(D - s) where k is the proportionality constant whose value depends on the specific commodity. Solve the above differential equation by expressing supply and demand as simply linear functions of price in the form S = aP - b and D = e - fP
Find the area of the surface obtained by rotating the circle x² + y² = r² about the line y = r.
1) Find the equation of the tangent line to the graph y=xe at the point (1, 1).
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