Scalar line integrals with arc length as parameter Evaluate the following line integrals. 13. ∫ C ( x 2 − 2 y 2 ) d s ; C is the line circle r ( s ) = ( s / 2 , s / 2 ) , for 0 ≤ s ≤ 4 .
Scalar line integrals with arc length as parameter Evaluate the following line integrals. 13. ∫ C ( x 2 − 2 y 2 ) d s ; C is the line circle r ( s ) = ( s / 2 , s / 2 ) , for 0 ≤ s ≤ 4 .
Solution Summary: The author evaluates the value of the line integral displaystyleundersetCint.
Scalar line integrals with arc length as parameterEvaluate the following line integrals.
13.
∫
C
(
x
2
−
2
y
2
)
d
s
;
C is the line circle
r
(
s
)
=
(
s
/
2
,
s
/
2
)
, for
0
≤
s
≤
4
.
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
Determine whether the lines
L₁ (t) = (-2,3, −1)t + (0,2,-3) and
L2 p(s) = (2, −3, 1)s + (-10, 17, -8)
intersect. If they do, find the point of intersection.
Convert the line given by the parametric equations y(t)
Enter the symmetric equations in alphabetic order.
(x(t)
= -4+6t
= 3-t
(z(t)
=
5-7t
to symmetric equations.
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