Scalar line integrals with arc length as parameter Evaluate the following line integrals. 13. ∫ C ( x 2 − 2 y 2 ) d s ; C is the line circle r ( s ) = ( s / 2 , s / 2 ) , for 0 ≤ s ≤ 4 .
Scalar line integrals with arc length as parameter Evaluate the following line integrals. 13. ∫ C ( x 2 − 2 y 2 ) d s ; C is the line circle r ( s ) = ( s / 2 , s / 2 ) , for 0 ≤ s ≤ 4 .
Solution Summary: The author evaluates the value of the line integral displaystyleundersetCint.
Scalar line integrals with arc length as parameterEvaluate the following line integrals.
13.
∫
C
(
x
2
−
2
y
2
)
d
s
;
C is the line circle
r
(
s
)
=
(
s
/
2
,
s
/
2
)
, for
0
≤
s
≤
4
.
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
Needed to be solved correclty in 30 minutes and get the thumbs up please show neat and clean work
Calculate the line integral shown in the image:
Curve C runs counterclockwise and is formed by the union of the following curves: the line segment at point (3,4) to point (0,2), the arc of the parabola y = 2-x² from (0.2) the point P where the parabola cuts the negative half-axis of the x and the line segment connecting P to the point (3,4).
Use Green's Theorem to evaluate the line integral. Assume the curve is oriented counterclockwise.
$(5)
(5x+ sinh y)dy - (3y² + arctan x²) dx, where C is the boundary of the square with vertices (1, 3), (2, 3), (2, 4), and (1,4).
false
(Type an exact answer.)
(5x + sinh yldy – (3y® + arctan x
an x²) dx =
dx =
...
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