Chemical Principles
Chemical Principles
8th Edition
ISBN: 9781305581982
Author: Steven S. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 14, Problem 23E

(a)

Interpretation Introduction

Interpretation: The Lewis structure, molecular structure and expected hybrid orbitals on central atom, polarity of CF4 molecule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The sum of valence electrons must be arranged in such a way that all atoms must get octet configuration (8 electrons).

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

The polarity of molecule is determined with the help of presence of polar bond and symmetrical geometry.

(a)

Expert Solution
Check Mark

Answer to Problem 23E

Molecular structure = Tetrahedral

Polarity = Non-polar

Hybridization = sp3

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  1

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in CF4 :

  (1×4)+(4×7)=32

Hence the best Lewis structure for CF4 must be:

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  2

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization = 4+ 0Hybridization =4= sp3 = tetrahedral (109 °)

(b)

Interpretation Introduction

Interpretation: The Lewis structure, molecular structure and expected hybrid orbitals on central atom, polarity of NF3 molecule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The sum of valence electrons must be arranged in such a way that all atoms must get octet configuration (8 electrons).

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

The polarity of molecule is determined with the help of presence of polar bond and symmetrical geometry.

(b)

Expert Solution
Check Mark

Answer to Problem 23E

Molecular structure = pyramid

Polarity = polar

Hybridization = sp3

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  3

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in NF3 :

  (1×5)+(3×7)=26

Hence the best Lewis structure for NF3 must be:

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  4

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization = 3+ 1Hybridization =4= sp3 = pyramid

(c)

Interpretation Introduction

Interpretation: The Lewis structure, molecular structure and expected hybrid orbitals on central atom, polarity of OF2 molecule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The sum of valence electrons must be arranged in such a way that all atoms must get octet configuration (8 electrons).

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

The polarity of molecule is determined with the help of presence of polar bond and symmetrical geometry.

(c)

Expert Solution
Check Mark

Answer to Problem 23E

Molecular structure = bent

Polarity = polar

Hybridization = sp3

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  5

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in OF2 :

  (1×6)+(2×7)=20

Hence the best Lewis structure for OF2 must be:

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  6

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization = 2+ 2Hybridization =4= sp3 = bent

(d)

Interpretation Introduction

Interpretation: The Lewis structure, molecular structure and expected hybrid orbitals on central atom, polarity of BF3 molecule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The sum of valence electrons must be arranged in such a way that all atoms must get octet configuration (8 electrons).

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

The polarity of molecule is determined with the help of presence of polar bond and symmetrical geometry.

(d)

Expert Solution
Check Mark

Answer to Problem 23E

Molecular structure = trigonal planer

Polarity = non-polar

Hybridization = sp2

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  7

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in BF3 :

  (1×3)+(3×7)=24

Hence the best Lewis structure for BF3 must be:

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  8

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization = 3+ 0Hybridization =3= sp2 = trigonal planer

(e)

Interpretation Introduction

Interpretation: The Lewis structure, molecular structure and expected hybrid orbitals on central atom, polarity of BeH2 molecule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The sum of valence electrons must be arranged in such a way that all atoms must get octet configuration (8 electrons).

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

The polarity of molecule is determined with the help of presence of polar bond and symmetrical geometry.

(e)

Expert Solution
Check Mark

Answer to Problem 23E

Molecular structure = linear

Polarity = non-polar

Hybridization = sp

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  9

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in BeH2 :

  (1×2)+(2×1)=4

Hence the best Lewis structure for BeH2 must be:

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  10

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization = 2+ 0Hybridization =2= sp = linear

(f)

Interpretation Introduction

Interpretation: The Lewis structure, molecular structure and expected hybrid orbitals on central atom, polarity of TeF4 molecule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The sum of valence electrons must be arranged in such a way that all atoms must get octet configuration (8 electrons).

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

The polarity of molecule is determined with the help of presence of polar bond and symmetrical geometry.

(f)

Expert Solution
Check Mark

Answer to Problem 23E

Molecular structure = see-saw

Polarity = polar

Hybridization = sp3d

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  11

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in TeF4 :

  (1×6)+(4×7)=34

Hence the best Lewis structure for TeF4 must be:

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  12

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization = 4+ 1Hybridization =5= sp3d = see-saw

(g)

Interpretation Introduction

Interpretation: The Lewis structure, molecular structure and expected hybrid orbitals on central atom, polarity of AsF5 molecule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The sum of valence electrons must be arranged in such a way that all atoms must get octet configuration (8 electrons).

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

The polarity of molecule is determined with the help of presence of polar bond and symmetrical geometry.

(g)

Expert Solution
Check Mark

Answer to Problem 23E

Molecular structure = trigonal bipyramid

Polarity = non-polar

Hybridization = sp3d

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  13

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in AsF5 :

  (1×5)+(5×7)=40

Hence the best Lewis structure for AsF5 must be:

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  14

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization = 5 +0  = 5  = sp3d = trigonal bipyramidal

(h)

Interpretation Introduction

Interpretation: The Lewis structure, molecular structure and expected hybrid orbitals on central atom, polarity of KrF2 molecule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The sum of valence electrons must be arranged in such a way that all atoms must get octet configuration (8 electrons).

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

The polarity of molecule is determined with the help of presence of polar bond and symmetrical geometry.

(h)

Expert Solution
Check Mark

Answer to Problem 23E

Molecular structure = linear

Polarity = non-polar

Hybridization = sp3d

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  15

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in KrF2 :

  (1×8)+(2×7)=22

Hence the best Lewis structure for KrF2 must be:

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  16

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization = 2 +3  = 5  = sp3d = linear

(i)

Interpretation Introduction

Interpretation: The Lewis structure, molecular structure and expected hybrid orbitals on central atom, polarity of KrF4 molecule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The sum of valence electrons must be arranged in such a way that all atoms must get octet configuration (8 electrons).

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

The polarity of molecule is determined with the help of presence of polar bond and symmetrical geometry.

(i)

Expert Solution
Check Mark

Answer to Problem 23E

Molecular structure = square planer

Polarity = non-polar

Hybridization = sp3d2

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  17

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in KrF4 :

  (1×8)+(4×7)=36

Hence the best Lewis structure for KrF4 must be:

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  18

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization = 4 +2  = 6  = sp3d2 = square planer due to presence of 2 lone pairs

(j)

Interpretation Introduction

Interpretation: The Lewis structure, molecular structure and expected hybrid orbitals on central atom, polarity of SeF6 molecule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The sum of valence electrons must be arranged in such a way that all atoms must get octet configuration (8 electrons).

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

The polarity of molecule is determined with the help of presence of polar bond and symmetrical geometry.

(j)

Expert Solution
Check Mark

Answer to Problem 23E

Molecular structure = octahedral

Polarity = non-polar

Hybridization = sp3d2

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  19

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in SeF6 :

  (1×6)+(6×7)=48

Hence the best Lewis structure for SeF6 must be:

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  20

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization =6 +0  = 6  = sp3d2 = octahedral

(k)

Interpretation Introduction

Interpretation: The Lewis structure, molecular structure and expected hybrid orbitals on central atom, polarity of IF5 molecule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The sum of valence electrons must be arranged in such a way that all atoms must get octet configuration (8 electrons).

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

The polarity of molecule is determined with the help of presence of polar bond and symmetrical geometry.

(k)

Expert Solution
Check Mark

Answer to Problem 23E

Molecular structure = square pyramid

Polarity = polar

Hybridization = sp3d2

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  21

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in IF5 :

  (1×7)+(5×7)=42

Hence the best Lewis structure for IF5 must be:

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  22

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization =5 +1 = 6  = sp3d2 = square pyramidal ( due to presence of 1 lone pair)

(l)

Interpretation Introduction

Interpretation: The Lewis structure, molecular structure and expected hybrid orbitals on central atom, polarity of IF3 molecule needs to be determined.

Concept Introduction:

Lewis dot structure is the representation which shows the bonding between atoms present in a molecule. It shows lone pairs and bond pairs that existing on each bonded atom. Lewis dot structure is also known as Lewis dot formula or electron dot structure.

The sum of valence electrons must be arranged in such a way that all atoms must get octet configuration (8 electrons).

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.

The polarity of molecule is determined with the help of presence of polar bond and symmetrical geometry.

(l)

Expert Solution
Check Mark

Answer to Problem 23E

Molecular structure = T-shape

Polarity = polar

Hybridization = sp3d

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  23

Explanation of Solution

The bond formation between the atoms takes place due to the sharing of valence electrons of bonded atoms while the remaining electrons present in outer shell represented as lone pair of electrons. To draw the Lewis structure, calculate the total number of valence electrons in each atom and draw the structure in such a way that each atom gets its octet configuration.

Total number of valence electrons in IF3 :

  (1×7)+(3×7)=28

Hence the best Lewis structure for IF3 must be:

  Chemical Principles, Chapter 14, Problem 23E , additional homework tip  24

  Hybridization = Number of sigma bonds + Number of lone pairs on bonded atoms.Hybridization = 3 +2  = 5  = sp3d = T-shape due to presence of 2 lone pair

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 14 Solutions

Chemical Principles

Ch. 14 - Prob. 11ECh. 14 - Prob. 12ECh. 14 - Prob. 13ECh. 14 - Use the localized electron model to describe the...Ch. 14 - Prob. 15ECh. 14 - Use the LE model to describe the bonding in H2CO...Ch. 14 - Prob. 17ECh. 14 - The space-filling models of hydrogen cyanide and...Ch. 14 - Prob. 19ECh. 14 - Prob. 20ECh. 14 - Prob. 21ECh. 14 - Indigo is the dye used in coloring blue jeans. The...Ch. 14 - Prob. 23ECh. 14 - Prob. 24ECh. 14 - Why must all six atoms in C2H4 be in the same...Ch. 14 - The allene molecule has the following Lewis...Ch. 14 - Biacetyl and acetoin are added to margarine to...Ch. 14 - Many important compounds in the chemical industry...Ch. 14 - Prob. 29ECh. 14 - Hot and spicy foods contain molecules that...Ch. 14 - Two molecules used in the polymer industry are...Ch. 14 - Prob. 32ECh. 14 - The three most stable oxides of carbon are carbon...Ch. 14 - Prob. 34ECh. 14 - Prob. 35ECh. 14 - What are the relationships among bond order, bond...Ch. 14 - Prob. 37ECh. 14 - A Lewis structure obeying the octet rule can be...Ch. 14 - Prob. 39ECh. 14 - Why does the molecular orbital model do a better...Ch. 14 - Prob. 41ECh. 14 - Prob. 42ECh. 14 - Prob. 43ECh. 14 - In which of the following diatomic molecules would...Ch. 14 - Prob. 45ECh. 14 - Using the molecular orbital model to describe the...Ch. 14 - The transport of O2 in the blood is carried out by...Ch. 14 - Prob. 48ECh. 14 - Prob. 49ECh. 14 - Consider the following electron configuration:...Ch. 14 - Prob. 51ECh. 14 - Using an MO energy-level diagram, would you expect...Ch. 14 - Use Figs.14.45 and 14.46 to answer the following...Ch. 14 - The diatomic molecule OH exists in the gas phase....Ch. 14 - Prob. 55ECh. 14 - Describe the bonding in the O3 molecule and the...Ch. 14 - Prob. 57ECh. 14 - The space-filling model for benzoic acid is shown...Ch. 14 - Prob. 59ECh. 14 - Prob. 60ECh. 14 - The microwave spectrum of 12C16O shows that the...Ch. 14 - Prob. 62ECh. 14 - Prob. 63ECh. 14 - Prob. 64ECh. 14 - Draw the Lewis structures, predict the molecular...Ch. 14 - Prob. 66AECh. 14 - Prob. 67AECh. 14 - Prob. 68AECh. 14 - Prob. 69AECh. 14 - Prob. 70AECh. 14 - Prob. 71AECh. 14 - Prob. 72AECh. 14 - Prob. 73AECh. 14 - Vitamin B6 is an organic compound whose deficiency...Ch. 14 - Prob. 75AECh. 14 - Prob. 76AECh. 14 - Prob. 77AECh. 14 - Prob. 78AECh. 14 - Prob. 79AECh. 14 - Draw the Lewis structures for TeCl4 , ICl5 , PCl5...Ch. 14 - Prob. 81AECh. 14 - Pelargondin is the molecule responsible for the...Ch. 14 - Prob. 83AECh. 14 - Prob. 84AECh. 14 - Prob. 85AECh. 14 - Prob. 86AECh. 14 - Given that the ionization energy of F2 is...Ch. 14 - Bond energy has been defined in the text as the...Ch. 14 - a.A flask containing gaseous N2 is irradiated with...Ch. 14 - Use the MO model to determine which of the...Ch. 14 - Cholesterol (C27H46O) has the following structure:...Ch. 14 - Arrange the following from lowest to highest...Ch. 14 - Carbon monoxide (CO) forms bonds to a variety of...Ch. 14 - Prob. 94CPCh. 14 - In Exercise71 in Chapter13 , the Lewis structures...Ch. 14 - Prob. 96CPCh. 14 - Prob. 97CPCh. 14 - Prob. 98MP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
  • Text book image
    Chemistry
    Chemistry
    ISBN:9781133611097
    Author:Steven S. Zumdahl
    Publisher:Cengage Learning
    Text book image
    Chemistry
    Chemistry
    ISBN:9781305957404
    Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
    Publisher:Cengage Learning
    Text book image
    Chemistry: An Atoms First Approach
    Chemistry
    ISBN:9781305079243
    Author:Steven S. Zumdahl, Susan A. Zumdahl
    Publisher:Cengage Learning
  • Text book image
    Chemistry: Principles and Practice
    Chemistry
    ISBN:9780534420123
    Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
    Publisher:Cengage Learning
    Text book image
    Chemistry & Chemical Reactivity
    Chemistry
    ISBN:9781133949640
    Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
    Publisher:Cengage Learning
    Text book image
    Chemistry & Chemical Reactivity
    Chemistry
    ISBN:9781337399074
    Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
    Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781133611097
Author:Steven S. Zumdahl
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
Text book image
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Stoichiometry - Chemistry for Massive Creatures: Crash Course Chemistry #6; Author: Crash Course;https://www.youtube.com/watch?v=UL1jmJaUkaQ;License: Standard YouTube License, CC-BY
Bonding (Ionic, Covalent & Metallic) - GCSE Chemistry; Author: Science Shorts;https://www.youtube.com/watch?v=p9MA6Od-zBA;License: Standard YouTube License, CC-BY
General Chemistry 1A. Lecture 12. Two Theories of Bonding.; Author: UCI Open;https://www.youtube.com/watch?v=dLTlL9Z1bh0;License: CC-BY