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(a)
To find: The graph of the parametric equations, initial and terminal points. Also, indicate the direction in which the curve is traced.
(a)
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Answer to Problem 16E
The graph of the parametric equations is shown in figure (1), and there are no initial and terminal points.
Explanation of Solution
Given information: The equations are
Calculation:
Use the following step to graph the parametric equations by graphing calculator.
Step 1: First press the “ON” button graphical calculator.
Step 2: Press the
Step 3: Press
Step 4: Press
Figure (1)
The graph is a linear equation so there are no initial and terminal points.
Therefore, the graph of the parametric equations is shown in figure (1), and there are no initial and terminal points.
(b)
To find: The Cartesian equation for a curve that contains the parameterized curve and the portion of the graph of the Cartesian equation that is traced by the parameterized curve.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 16E
The Cartesian equation for a curve that contains the parameterized curve is
Explanation of Solution
Given information: The equations are
Calculation:
Rewrite the parametric equation
Substitute
As shown in the graph, the entire line is graphed so the parameterized curve traces the entire Cartesian equation.
Therefore, the Cartesian equation for a curve that contains the parameterized curve is
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Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)
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