Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)

4th Edition

ISBN: 9780133178579

Author: Ross L. Finney

Publisher: PEARSON

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Question

Chapter 1, Problem 10RE

To determine

To find: The equation of line that passes through (−2,−3) and perpendicular to a given line.

Expert Solution & Answer

Answer to Problem 10RE

The required equation of specified line is y=−53x−193 .

Explanation of Solution

Given information: The point is (−2,−3) and the perpendicular line is 3x−5y=1 .

Formula used: The point-slope form an equation of line is:

y−y1=m(x−x1) ......(1)

Calculation:

Rearrange the given equation.

3x−5y=15y=3x−1y=35x−15

Compare the given equation with standard equation y=mx+b .

m=35

If a line is perpendicular to the other then the slope of other line is negative reciprocal of one line. So, the slope of its perpendicular line is:

slope=−53

Substitute −2 for x1 , −3 for y1 , and −53 for m in the equation (1).

y−(−3)=−53(x−(−2))y+3=−53x−103y=−53x−193

Therefore, the required equation of specified line is y=−53x−193 .

Chapter 1, Problem 9RE

Chapter 1, Problem 11RE

Chapter 1 Solutions

Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)

Ch. 1.1 - Prob. 1QR Ch. 1.1 - Prob. 2QR Ch. 1.1 - Prob. 3QR Ch. 1.1 - Prob. 4QR Ch. 1.1 - Prob. 5QR Ch. 1.1 - Prob. 6QR Ch. 1.1 - Prob. 7QR Ch. 1.1 - Prob. 8QR Ch. 1.1 - Prob. 9QR Ch. 1.1 - Prob. 10QR

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The equation of line that passes through ( − 2 , − 3 ) and perpendicular to a given line.