Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)

4th Edition

ISBN: 9780133178579

Author: Ross L. Finney

Publisher: PEARSON

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Question

Chapter 1, Problem 11RE

To determine

To find: The equation of line that passes through (−1,2) and perpendicular to a given line.

Expert Solution & Answer

Answer to Problem 11RE

The required equation of specified line is y=23x+83 .

Explanation of Solution

Given information: The point is (−1,2) and the perpendicular line is 12x+13y=1 .

Formula used: The point-slope form an equation of line is:

y−y1=m(x−x1) ...... (1)

Calculation:

Rearrange the given equation.

12x+13y=113y=−12x+1y=−32x+3

Compare the given equation with standard equation of line y=mx+b .

m=−32

If a line is perpendicular to the other then the slope of other line is negative reciprocal of one line. So, the slope of its perpendicular line is:

slope=23

Substitute −1 for x1 , 2 for y1 , and 23 for m in the equation (1).

y−2=23(x−(−1))y−2=23x+23y=23x+23+2y=23x+83

Therefore, the required equation of specified line is y=23x+83 .

Chapter 1, Problem 10RE

Chapter 1, Problem 12RE

Chapter 1 Solutions

Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)

Ch. 1.1 - Prob. 1QR Ch. 1.1 - Prob. 2QR Ch. 1.1 - Prob. 3QR Ch. 1.1 - Prob. 4QR Ch. 1.1 - Prob. 5QR Ch. 1.1 - Prob. 6QR Ch. 1.1 - Prob. 7QR Ch. 1.1 - Prob. 8QR Ch. 1.1 - Prob. 9QR Ch. 1.1 - Prob. 10QR

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The equation of line that passes through ( − 1 , 2 ) and perpendicular to a given line.

Concept explainers

Videos

To find: The equation of line that passes through (−1,2) and perpendicular to a given line.

Answer to Problem 11RE

Explanation of Solution

Chapter 1 Solutions

Additional Math Textbook Solutions