Chapter 1.2, Problem 62E

To determine

To find: The correct option for the area $A$ of the rectangle as a function of its width.

Answer to Problem 62E

The correct option is (C) such that the area of the rectangle as a function of its width is $A\left(W\right)=2W^2$ .

Explanation of Solution

Given information: The length $L$ of the rectangle is twice long as long as its width $W$ .

The formula for the area of the rectangle is length times the breadth.

  $A=L\times W$

It is given that the length $L$ of the rectangle is twice long as long as its width. So,

  $L=2W$

Substitute $2W$ for $L$ in the area formula.

  $\begin{array}{c}A=2W\times W\\ =2W^2\end{array}$

Therefore, the correct option is (C) such that the area of the rectangle as a function of its width is $A\left(W\right)=2W^2$ .