Chapter 13.8, Problem 8CYU

To determine

Find the amplitude, period and vertical shift and equation of the midline for each function. Also, draw the graph of the function.

Answer to Problem 8CYU

The amplitude, period and vertical shift and the equation of the midline of the function is $doesnotexist,{360}^{\circ },\text{vertical shifts}:5unit\mathrm{s}down,y=-5$ .

Explanation of Solution

Given: It is given in the question that the function is $y=\sec \theta -5$ .

Concept Used:

In this, use the concept of the general equation for secant $y=a\sec b\theta +d$ , where a is amplitude which does not exist, $\frac{2\pi }{\left|b\right|}$ is period and d is the vertical shift and y = d is midline.

Calculation: Here, the function is $y=\sec \theta -5$ .

In this, $a=1$ , but it is a secant function so amplitude does not exist.

Now, the value of b is $1$ , so the period is: $\frac{2\pi }{\left|b\right|}=\frac{360}{\left|1\right|}={360}^{\circ }$

From the equation it is seen that $d=-5$ so the vertical shifts is five units down.

Also, $d=-5$ then the midline is $y=-5$ .

The graph of the function is given below:

  

Conclusion:

The amplitude, period and vertical shift and the equation of midline are $doesnotexist,{360}^{\circ },\text{vertical shifts}:5unit\mathrm{s}down,y=-5$ .