Chapter 13, Problem 29SGR

To determine

To find: About how far will the ball travel in $10$ seconds.

Answer to Problem 29SGR

Horizontal distance travelled by the ball $=x=17.1$ meters.

Explanation of Solution

Given information:

  $x=v_0\left(\cos \theta \right)t$

Where

Initial velocity $=v_0=5$ meters per second

Angle at which it thrown $=\theta ={70}^0$

Time $=t=10$ seconds

  $x$ represents the horizontal distance travelled by the ball.

Given

  $x=v_0\left(\cos \theta \right)t$

Where

Initial velocity $=v_0=5$ meters per second

Angle at which it thrown $=\theta ={70}^0$

Time $=t=10$ seconds

  $x$ represents the horizontal distance travelled by the ball.

On substituting values

We get

  $\begin{array}{l}x=v_0\left(\cos \theta \right)t\\ \Rightarrow x=5\left(\cos {70}^0\right)10\\ \Rightarrow x=50\left(\cos {70}^0\right)\\ \Rightarrow x=50\left(0.342\right)\\ \Rightarrow x=17.1\end{array}$

Therefore,

Horizontal distance travelled by the ball $=x=17.1$ meters.